SL 1.4 — Financial applications of geometric sequences
Formula (given in booklet): \( FV = PV \times \left(1 + \frac{r}{100k}\right)^{kn} \)
where \( r \) = annual rate (%), \( k \) = compounding periods per year, \( n \) = years
► In IB, always use the TVM solver on your GDC instead of this formula. The formula is given for understanding — the GDC is faster and less error-prone.
TVM Solver Setup — Compound Interest
N
Total number of compounding periods ( \( k \times n \) )
I%
Annual interest rate (always per annum, never divide yourself)
PV
Present value — negative if you're paying/investing
PMT
Payment per period (0 for simple compound interest)
FV
Future value — positive if you receive it
P/Y
= C/Y always in IB (compounding periods per year)
✗Sign convention: Money OUT is negative, money IN is positive. If you invest \$5000, PV = −5000. If you receive the future value, FV is positive.
Worked Example — Compound Interest
\$10 000 invested at 4.8% compounded monthly for 6 years. Find the future value.
Method: Depreciation of \( d\% \) per year keeps a fraction \( (1 - d/100) \). Model as \( FV = PV(1 - d/100)^n \), or on the TVM solver set I% = \( -d \).
Worked Example — Car Depreciation
A car worth \$18 000 depreciates 12% per year. Find its value after 5 years.
►Simple vs compound: Simple interest is arithmetic — the same amount each year (\( I = PV \times r/100 \) per year, total \( = PV(1 + rn/100) \)). Compound interest is geometric — interest earns interest. The TVM solver models compound; don't use it for simple-interest questions.
Method: To find the outstanding balance after \( k \) payments, use the TVM solver with N = \( k \) (payments made so far) and solve for FV. That FV is the remaining balance.
Worked Example — Outstanding Balance
From the car loan above (\$25 000 at 6.9%, 60 monthly payments of \$493.85). Find the balance after 24 payments.
►Increasing payments: If someone raises their payment, find the outstanding balance first, then use that as the new PV with the new PMT to find the new N.
6
Inflation, Real Value & Compounding Frequency
SL 1.7 — Financial modelling with technology
Real (inflation-adjusted) value: If inflation is \( i\% \) per year, the real value of a future sum in \( n \) years is \( \dfrac{\text{nominal value}}{(1 + i/100)^n} \).
Worked Example — Real Value
A sum grows at 5% nominal for 4 years while inflation runs at 2% per year. Find the real growth.
Nominal factor over 4 years: \( 1.05^4 = 1.21551 \)
Real value = \( \dfrac{1.05^4}{1.02^4} = \dfrac{1.21551}{1.08243} = 1.12294 \)
Real growth ≈ 12.29% over 4 years, ≈ 2.94% per year
Effective annual rate (EAR): \( \text{EAR} = \left[\left(1 + \dfrac{r}{100k}\right)^k - 1\right] \times 100\% \) — converts a nominal rate \( r\% \) compounded \( k \) times a year into one equivalent annual %.
Worked Example — Compounding Frequency
Compare 6% nominal on \$1000 over 1 year at different compounding frequencies.
Frequency
k
FV
EAR
Annually
1
\$1060.00
6.00%
Monthly
12
\$1061.68
6.17%
Daily
365
\$1061.83
6.18%
More frequent compounding gives a higher FV and EAR — keep P/Y = C/Y to match.
7
Things to Watch Out For
✗"Per annum" means per year. I% is always the annual rate. Never divide I% yourself — the calculator handles it using P/Y.
✗P/Y = C/Y in IB. Always set both to the same value (compounding frequency per year).
✗Rounding the final payment. If N = 68.3 months, the borrower makes 68 full payments plus a smaller final payment. Find it by solving with N = 68 for FV, then that FV plus one month's interest = final payment.
✗"How much interest was paid?" = Total payments − original loan. Include the final smaller payment if N is not a whole number.
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