jmaths
IB Mathematics: Applications and Interpretation HL · AHL 6: Complex Numbers · AHL 6.1
Name Date
The number i and Cartesian form Problem set B
Show your working. Work by hand first, then check with the calculator in complex mode.
Each question matches the question with the same number in set A. Do the ones you got wrong there.
Difficulty: first skills applying them stretch
Skills
-
Simplify each expression, giving the answer in the form \(x + iy\).
- (a) \(i^{18}\)
- (b) \(5i^{7}\)
- (c) \((3i)^2\)
- (d) \((5i)^3\)
-
Answer each part.
- (a) \(\sqrt{-64}\)
- (b) \(\sqrt{-75}\)
- (c) State the real part and the imaginary part of \(-2 - \sqrt{-49}\).
-
Simplify each expression.
- (a) \((-4 + 7i) + (8 - 3i)\)
- (b) \((6 - 2i) - (-5 + 4i)\)
-
Expand and simplify, giving each answer in the form \(x + iy\).
- (a) \((2 - 3i)(5 + i)\)
- (b) \((4 + i)(-3 - 2i)\)
-
Expand and simplify.
- (a) \((5 - 3i)^2\)
- (b) \((1 + 6i)^2\)
-
Simplify each expression, giving the answer in the form \(x + iy\).
- (a) \((1 + 4i)^2 + 2i(3 - i)\)
- (b) \(3(2 - i)(1 + 2i) - 4i^3\)
-
Use your calculator to check complex arithmetic.
- (a) Set the calculator to complex mode. Evaluate \((3 + 4i)(5 - 2i)\) and write the result in the form \(x + iy\).
- (b) What does the calculator show for \(\sqrt{-25}\) in complex mode?
-
Ana writes \((5 + 2i)(5 - 2i) = 25 - 4i^2 = 21\). Ben writes the answer as \(29\).
- (a) Which of them is right? Explain the mistake.
- (b) \((-1 + 4i) - (2 + 3i)\) Simplify, and say why no \(i^2\) step is needed.
In context
-
Two sensors report a signal as complex numbers, in millivolts: \(p = 4 - 3i\) and \(q = -1 + 8i\). The combined signal is \(s = p + q\). A filter multiplies the combined signal by the gain \(g = 3 + i\), so the output is \(gs\).
- (a) Find the combined signal \(s\).
- (b) Find the output \(gs\) in the form \(x + iy\).
Stretch
-
The powers of i repeat in a cycle of four.
- (a) Find \(i + i^2 + i^3 + i^4\).
- (b) Hence find \(i + i^2 + i^3 + \dots + i^{47}\).
-
This question uses a square to find a high power.
- (a) Show that \((1 - i)^2 = -2i\).
- (b) Hence find \((1 - i)^{6}\).
jmaths.xyz · AI HL · AHL 6.1 The number i and Cartesian form