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IB Mathematics: Applications and Interpretation HL · AHL 6: Complex Numbers · AHL 6.12
Complex numbers on the Argand diagram Problem set A Worked solutions
Skills
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The diagram shows the points that represent the complex numbers \(z\) and \(w\).
(a) Write down \(z\) and \(w\) as complex numbers.
- \(z\) is the point \((1, 4)\) and \(w\) is the point \((5, -2)\).
(b) Find \(z + w\) and mark it on a copy of the diagram, using the parallelogram rule.
- \(z + w = (1 + 4 i) + (5 - 2 i) = 6 + 2 i\)
- Complete the parallelogram with corners \(0\), \(z\), \(w\). The fourth corner is the point \((6, 2)\).
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The diagram shows the points that represent \(z\) and \(w\).
(a) Write down \(-w\) and mark it on a copy of the diagram.
- \(w = 3 + 2 i \Rightarrow -w = -3 - 2 i\)
- \(-w\) is \(w\) reflected through the origin (rotated through \(\pi\) about the origin).
(b) Find \(z - w\) and mark it on the diagram.
- \(z - w = z + (-w) = (-1 + 5 i) + (-3 - 2 i) = -4 + 3 i\)
- Complete the parallelogram with corners \(0\), \(z\), \(-w\). The fourth corner is \((-4, 3)\).
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The diagram shows the points that represent \(z\) and \(\alpha\). The dashed line joins them.
(a) Write down \(z\) and \(\alpha\) as complex numbers.
- \(z\) is the point \((2, 5)\). \(\alpha\) is the point \((6, 1)\).
(b) Find \(z - \alpha\).
- \(z - \alpha = (2 + 5 i) - (6 + i) = -4 + 4 i\)
(c) The vector from the point \(\alpha\) to the point \(z\) is \(z - \alpha\). Find the distance between the two points, to 3 significant figures.
- \(|z - \alpha| = \sqrt{(-4)^2 + (4)^2} = \sqrt{32} = 5.66\)
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The triangle PQR has vertices P(2, 0), Q(4, 0) and R(4, 3).
(a) Find the modulus and argument of \(1 + i\).
- \(|1 + i| = \sqrt{(1)^2 + (1)^2} = \sqrt{2}\)
- \(\arg = \frac{\pi}{4}\) (use the quadrant and the reference angle).
(b) Every vertex is multiplied by \(1 + i\) to give the triangle P′Q′R′. Find the new vertices.
- \(P' = (2)(1 + i) = 2 + 2 i\)
- \(Q' = (4)(1 + i) = 4 + 4 i\)
- \(R' = (4 + 3 i)(1 + i) = 1 + 7 i\)
(c) Describe the transformation that takes the first triangle to the second.
- Multiplying by a complex number rotates a point by its argument and scales its distance from the origin by its modulus.
- So the triangle is rotated through \(\frac{\pi}{4}\) anticlockwise about the origin and enlarged by scale factor \(\sqrt{2}\).
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\(OAB\) is an equilateral triangle. \(O\) is the origin and \(A\) is the point \((6, 2)\).
(a) Write the rotation of \(A\) through \(\frac{\pi}{3}\) anticlockwise about \(O\) as a multiplication, and find the third vertex \(B\) above the line \(OA\).
- \(B = (6 + 2 i)\,\mathrm{cis}\left(\tfrac{\pi}{3}\right) = (6 + 2 i)\left(\tfrac{1}{2} + \tfrac{\sqrt{3}}{2}i\right)\)
- \(= 3 - \sqrt{3} + \left(1 + 3 \sqrt{3}\right) i\)
- \(B\) is the point \((3 - \sqrt{3}, 1 + 3 \sqrt{3})\).
(b) Find the other point \(C\) that makes \(OAC\) equilateral, below the line \(OA\).
- \(C = (6 + 2 i)\,\mathrm{cis}\left(-\tfrac{\pi}{3}\right) = (6 + 2 i)\left(\tfrac{1}{2} - \tfrac{\sqrt{3}}{2}i\right) = \sqrt{3} + 3 + \left(1 - 3 \sqrt{3}\right) i\)
- \(C\) is the point \((\sqrt{3} + 3, 1 - 3 \sqrt{3})\).
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The diagram shows the points that represent \(z\) and \(w\). Give each argument in the range \(-\pi < \theta \le \pi\).
(a) Write down \(z\) and \(w\), and find their moduli and arguments.
- \(z = -4 + 4i\) is in the second quadrant: \(|z| = \sqrt{16 + 16} = 4\sqrt{2}\), \(\arg z = \pi - \frac{\pi}{4} = \frac{3\pi}{4}\).
- \(w = 2i\) is on the positive imaginary axis: \(|w| = 2\), \(\arg w = \frac{\pi}{2}\).
(b) Find the modulus and argument of \(\dfrac{z}{w}\).
- \(\left|\frac{z}{w}\right| = \frac{4\sqrt{2}}{2} = 2\sqrt{2}\)
- \(\arg\frac{z}{w} = \frac{3\pi}{4} - \frac{\pi}{2} = \frac{\pi}{4}\)
(c) Describe the transformation that takes the point \(z\) to the point \(\dfrac{z}{w}\), and write \(\dfrac{z}{w}\) in the form \(x + iy\).
- Dividing by \(w\) turns the point back through \(\arg w = \frac{\pi}{2}\) (clockwise) and divides its distance from the origin by \(|w| = 2\).
- \(\frac{z}{w} = 2\sqrt{2}\left(\cos\frac{\pi}{4} + i\sin\frac{\pi}{4}\right) = 2 + 2i\).
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The point \(z = 6 + 5i\) is turned through \(\frac{\pi}{2}\) clockwise about the point \(\alpha = 1 + 2i\), shown on the diagram.
(a) Find \(z - \alpha\).
- \(z - \alpha = (6 + 5i) - (1 + 2i) = 5 + 3i\)
(b) Multiply \(z - \alpha\) by \(\mathrm{cis}\left(-\frac{\pi}{2}\right) = -i\).
- \((5 + 3i)(-i) = 3 - 5i\), using \(i^2 = -1\).
(c) Hence find the image \(z'\) of \(z\).
- \(z' = \alpha + (3 - 5i) = 4 - 3i\).
- Check: \(|z' - \alpha| = |3 - 5i| = |z - \alpha|\).
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The point \(z\) is mapped to the point \(w\) by \(w = -2iz + 4\).
(a) Find \(w\) when \(z = 1 + 2i\).
- \(w = -2i(1 + 2i) + 4 = -2i - 4i^2 + 4 = -2i + 4 + 4 = 8 - 2i\)
(b) Describe the two transformations that map the point \(z\) onto the point \(w\), in the order they are applied.
- \(-2i\) has modulus 2 and argument \(-\frac{\pi}{2}\), so multiplying by it rotates \(\frac{\pi}{2}\) clockwise and enlarges by a scale factor 2 about the origin.
- Adding 4 then translates every point 4 units to the right.
(c) Find \(z\) when \(w = 6 + 4i\).
- \(w - 4 = 2 + 4i\)
- \(z = \dfrac{2 + 4i}{-2i} = \dfrac{(2 + 4i)(i)}{2} = \dfrac{2i - 4}{2} = -2 + i\)
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The complex numbers are \(z = 2 + 4i\) and \(w = 6e^{0.4i}\).
(a) Find \(|z|\) and \(\arg z\), to 3 significant figures.
- \(|z| = \sqrt{2^2 + 4^2} = 4.47\)
- \(\arg z = \tan^{-1}\dfrac{4}{2} = 1.11\) (first quadrant).
(b) Find the angle between the line from \(0\) to \(z\) and the line from \(0\) to \(w\).
- \(\arg w = 0.4\), so the angle between the lines is \(|0.4 - 1.107| = 0.707\) radians.
(c) Find the area of the triangle on an Argand diagram with vertices at \(0\), \(z\) and \(w\), to 3 significant figures.
- \(\text{Area} = \tfrac{1}{2}|z||w|\sin\varphi = \tfrac{1}{2}(4.472)(6)\sin 0.7071 = 8.72\).
In context
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Two tugs pull a barge. Each force, in newtons, is written as a complex number: the real part is the force east and the imaginary part is the force north. The forces are \(z = 300 + 100i\) and \(w = 150 - 250i\).
(a) Find the resultant, \(z + w\), of the two.
- \(z + w = (300 + 100 i) + (150 - 250 i) = 450 - 150 i\)
- Real parts add and imaginary parts add: this is the parallelogram rule.
(b) Find the magnitude of the resultant, to 3 significant figures.
- \(|z + w| = \sqrt{(450)^2 + (-150)^2} = 474\)
(c) Find \(z - w\), the vector from \(w\) to \(z\).
- \(z - w = (300 + 100 i) - (150 - 250 i) = 150 + 350 i\)
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A lighthouse is at the point \(\alpha = 3 + 8i\) on a map, where 1 unit is 1 km. A boat is at the point \(z = 11 + 2i\).
(a) Find \(z - \alpha\) and say what it represents.
- \(z - \alpha = (11 + 2 i) - (3 + 8 i) = 8 - 6 i\)
- It is the vector (displacement) from the lighthouse \(\alpha\) to the boat \(z\).
(b) Find how far the boat is from the lighthouse, to 3 significant figures.
- \(|z - \alpha| = \sqrt{(8)^2 + (-6)^2} = 10\)
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A designer draws a logo as a triangle with vertices A(1, 0); B(3, 0); C(1, 2). A program multiplies every vertex by the complex number \(3 i\).
(a) Describe the effect on the shape of multiplying every vertex by that number.
- \(|3i| = 3,\ \arg 3i = \frac{\pi}{2}\)
- The shape is rotated through \(\frac{\pi}{2}\) anticlockwise about the origin and enlarged by scale factor \(3\).
(b) Find the vertices of the new shape.
- \(A' = (1) \times (3 i) = 3 i\)
- \(B' = (3) \times (3 i) = 9 i\)
- \(C' = (1 + 2 i) \times (3 i) = -6 + 3 i\)
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A stage turntable has its centre at \(\alpha = 3 + 2i\), where the units are metres on a plan. A loudspeaker stands at \(z = 8 + 5i\). The turntable turns the loudspeaker through 0.7 radians anticlockwise about its centre.
(a) Find \(z - \alpha\).
- \(z - \alpha = (8 + 5i) - (3 + 2i) = 5 + 3i\)
(b) Find the new position of the loudspeaker, with the real and imaginary parts to 3 significant figures.
- \(z' = \alpha + (z - \alpha)\,\mathrm{cis}\,0.7 = (3 + 2i) + (5 + 3i)(\cos 0.7 + i\sin 0.7)\)
- \(z' = 4.89 + 7.52i\) (radian mode).
(c) Find how far the loudspeaker is from the centre of the turntable after the turn, to 3 significant figures.
- \(|z' - \alpha| = |z - \alpha| = \sqrt{5^2 + 3^2} = \sqrt{34} = 5.83\) m. A turn does not change the distance from the centre.
Stretch
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\(OPQR\) is a square with \(O\) at the origin and \(P\) at the point \(4 + 2i\). \(R\) is above the line \(OP\).
(a) Find the point \(R\), by rotating \(P\) through \(\frac{\pi}{2}\) anticlockwise about \(O\).
- \(\mathrm{cis}\left(\tfrac{\pi}{2}\right) = i\)
- \(R = i(4 + 2 i) = -2 + 4 i\)
(b) Find the point \(Q\).
- \(Q = P + R = (4 + 2 i) + (-2 + 4 i) = 2 + 6 i\)
- The corner \(Q\) completes the parallelogram \(OPQR\), which is a square.
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\(PQR\) is an equilateral triangle. \(P\) is the point \(p = 2 + i\) and \(Q\) is the point \(q = 6 + 4i\). \(R\) is on the left of the line \(PQ\) as you go from \(P\) to \(Q\). Neither vertex is at the origin, so use \(q - p\).
(a) Find \(q - p\), the vector from \(P\) to \(Q\).
- \(q - p = (6 + 4 i) - (2 + i) = 4 + 3 i\)
(b) Rotate this vector through \(\frac{\pi}{3}\) anticlockwise about \(P\) by multiplying it by \(\mathrm{cis}\left(\frac{\pi}{3}\right)\). Hence find the vector from \(P\) to \(R\).
- \((4 + 3 i)\left(\tfrac{1}{2} + \tfrac{\sqrt{3}}{2}i\right) = 2 - \frac{3 \sqrt{3}}{2} + \left(\frac{3}{2} + 2 \sqrt{3}\right) i\)
(c) Find the coordinates of \(R\).
- \(r = p + (2 - \frac{3 \sqrt{3}}{2} + \left(\frac{3}{2} + 2 \sqrt{3}\right) i) = 4 - \frac{3 \sqrt{3}}{2} + \left(\frac{5}{2} + 2 \sqrt{3}\right) i\)
- \(R\) is the point \((4 - \frac{3 \sqrt{3}}{2}, \frac{5}{2} + 2 \sqrt{3})\).
jmaths.xyz · AI HL · AHL 6.12 Geometry on the Argand diagram