jmaths
IB Mathematics: Applications and Interpretation HL · 12.9: Differentiation · 12.9.6
Expanding, splitting and increasing or decreasing Problem set A Answers
Skills
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- (a) \(\frac{dy}{dx}=8a + \frac{10b}{x^{3}}\)
- (b) \(\frac{dy}{dx}=12b^{2}x^{2} - \frac{6a}{cx^{2}}\)
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- (a) \(\frac{dy}{dx}=2b^{2}x\)
- (b) \(\frac{dy}{dx}=32a^{2}x\)
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- (a) \(\frac{dy}{dx}=2x + p + q\)
- (b) \(\frac{dy}{dx}=2pqx + p^{2} + q^{2}\)
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- (a) \(\frac{dy}{dx}=-\frac{12}{x^{2}}\)
- (b) \(\frac{dy}{dx}=\frac{1}{x^{2}} - \frac{6}{x^{3}}\)
- (c) \(\frac{dy}{dx}=4x + \frac{1}{2}\)
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- (a) \(x<2\)
- (b) \(x>5\)
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- (a) \(x>3\)
- (b) \(x>-\frac{b}{2}\)
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\(\frac{ds}{dt}=8 + \frac{9}{t^{2}}\)
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\(\frac{dy}{dx}=10x - 3\)
In context
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- (a) \(\frac{dH}{dT}=cm\)
- (b) 2.25 joules per °C
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- (a) \(\frac{d\theta}{dd}=-\frac{k}{d^2}\)
- (b) \(-\frac{\theta^2}{k}\)
- (c) 4
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- (a) \(\frac{dH}{dd}=q+4qd\)
- (b) A plant does not get shorter, so \(\frac{dH}{dd}>0\). That needs q > 0.
Stretch
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\(f'(x)=9x^2+4>0\) for all x
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- (a) \(f'(x)=\frac{1}{2} - \frac{k}{2x^{2}}\)
- (b) k = 2
jmaths.xyz · AI HL · 12.9.6 Expanding, splitting fractions and increasing or decreasing