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IB Mathematics: Applications and Interpretation HL · AHL 3: Further Integration · AHL 3.2

Integrating f(ax+b) and by inspection Problem set A One question at a time

Try each question on paper first. Open the working a line at a time, then say whether you had it.

Skills

  1. Find each integral.

    1. (a) \(\int \sqrt{5x-2}\,dx\)

      • Integrate as normal, treating the inside as x (add 1 to the power and divide by the new power, 3/2): \(\frac{2}{3}(5x-2)^{\frac{3}{2}}\).
      • Divide by 5, the coefficient of x: \(\frac{2}{3}\div5=\frac{2}{15}\).
      • \(\int \sqrt{5x-2}\,dx=\frac{2}{15}(5x-2)^{\frac{3}{2}}+c\)
    2. (b) \(\int \sqrt[3]{4x+3}\,dx\)

      • Integrate as normal, treating the inside as x (add 1 to the power and divide by the new power, 4/3): \(\frac{3}{4}(4x+3)^{\frac{4}{3}}\).
      • Divide by 4, the coefficient of x: \(\frac{3}{4}\div4=\frac{3}{16}\).
      • \(\int \sqrt[3]{4x+3}\,dx=\frac{3}{16}(4x+3)^{\frac{4}{3}}+c\)
  2. Find \(\int 12(3x+1)^{-\frac{4}{3}}\,dx\).

    • Integrate as normal, treating the inside as x (add 1 to the power and divide by the new power, -1/3): \(-36(3x+1)^{-\frac{1}{3}}\).
    • Divide by 3, the coefficient of x: \(-36\div3=-12\).
    • \(\int 12(3x+1)^{-\frac{4}{3}}\,dx=-12(3x+1)^{-\frac{1}{3}}+c\)
  3. Find each integral.

    1. (a) \(\int \cos(4x-1)\,dx\)

      • Integrate as normal, treating the inside as x (the integral of cos is sin): \(\sin(4x-1)\).
      • Divide by 4, the coefficient of x: \(1\div4=\frac{1}{4}\).
      • \(\int \cos(4x-1)\,dx=\frac{1}{4}\sin(4x-1)+c\)
    2. (b) \(\int 5\cos(2x+3)\,dx\)

      • Integrate as normal, treating the inside as x (the integral of cos is sin): \(5\sin(2x+3)\).
      • Divide by 2, the coefficient of x: \(5\div2=\frac{5}{2}\).
      • \(\int 5\cos(2x+3)\,dx=\frac{5}{2}\sin(2x+3)+c\)
  4. Find each integral.

    1. (a) \(\int \sin(3x+2)\,dx\)

      • Integrate as normal, treating the inside as x (the integral of sin is minus cos): \(-\cos(3x+2)\).
      • Divide by 3, the coefficient of x: \(-1\div3=-\frac{1}{3}\).
      • \(\int \sin(3x+2)\,dx=-\frac{1}{3}\cos(3x+2)+c\)
    2. (b) \(\int 4\sin(1-2x)\,dx\)

      • Integrate as normal, treating the inside as x (the integral of sin is minus cos): \(-4\cos(1-2x)\).
      • Divide by -2, the coefficient of x: \(-4\div(-2)=2\).
      • \(\int 4\sin(1-2x)\,dx=2\cos(1-2x)+c\)
  5. Find each integral.

    1. (a) \(\int 4e^{5x+1}\,dx\)

      • Integrate as normal, treating the inside as x (the integral of e to a power is itself): \(4e^{5x+1}\).
      • Divide by 5, the coefficient of x: \(4\div5=\frac{4}{5}\).
      • \(\int 4e^{5x+1}\,dx=\frac{4}{5}e^{5x+1}+c\)
    2. (b) \(\int 10e^{1-2x}\,dx\)

      • Integrate as normal, treating the inside as x (the integral of e to a power is itself): \(10e^{1-2x}\).
      • Divide by -2, the coefficient of x: \(10\div(-2)=-5\).
      • \(\int 10e^{1-2x}\,dx=-5e^{1-2x}+c\)
  6. Find each integral.

    1. (a) \(\int \frac{6}{2x+5}\,dx\)

      • Integrate as normal, treating the inside as x (the integral of 1/u is ln|u|): \(6\ln|2x+5|\).
      • Divide by 2, the coefficient of x: \(6\div2=3\).
      • \(\int \frac{6}{2x+5}\,dx=3\ln|2x+5|+c\)
    2. (b) \(\int \frac{3}{4-3x}\,dx\)

      • Integrate as normal, treating the inside as x (the integral of 1/u is ln|u|): \(3\ln|4-3x|\).
      • Divide by -3, the coefficient of x: \(3\div(-3)=-1\).
      • \(\int \frac{3}{4-3x}\,dx=-\ln|4-3x|+c\)
  7. Find \(\int 12x^{3}(x^4-2)^{3}\,dx\).

    • Spot the pair: \(g(x)=x^4-2\) and \(g'(x)=4x^{3}\).
    • The integrand is \(3g'(x)[g(x)]^{3}\), so the integral is \(3\times\frac{(x^4-2)^{4}}{4}\).
    • \(\int 12x^{3}(x^4-2)^{3}\,dx=\frac{3}{4}(x^4-2)^{4}+c\)
    • Check: differentiate the answer and you get the integrand back.
  8. Find each integral.

    1. (a) \(\int 5\cos x\sin^{4}x\,dx\)

      • \(\cos x\) is the derivative of \(\sin x\): take \(g(x)=\sin x\).
      • The integral is \(5\times\frac{\sin^{5}x}{5}\).
      • \(\int 5\cos x\sin^{4}x\,dx=\sin^{5}x+c\)
      • Check: differentiate the answer and you get the integrand back.
    2. (b) \(\int \sin x\cos^{2}x\,dx\)

      • \(\sin x\) is minus the derivative of \(\cos x\): take \(g(x)=\cos x\), \(g'(x)=-\sin x\).
      • Allow for the minus sign: the integral is \(-\frac{\cos^{3}x}{3}\).
      • \(\int \sin x\cos^{2}x\,dx=-\frac{1}{3}\cos^{3}x+c\)
      • Check: differentiate the answer and you get the integrand back.
  9. Find each integral.

    1. (a) \(\int \frac{4x}{x^2+7}\,dx\)

      • Spot the pair: \(g(x)=x^2+7\) and \(g'(x)=2x\).
      • The top is \(2g'(x)\), so the integral is \(2\ln|g(x)|\).
      • \(\int \frac{4x}{x^2+7}\,dx=2\ln|x^2+7|+c\)
      • Check: differentiate the answer and you get the integrand back.
    2. (b) \(\int \frac{3x^{2}}{x^3+2}\,dx\)

      • Spot the pair: \(g(x)=x^3+2\) and \(g'(x)=3x^{2}\).
      • The top is exactly \(g'(x)\), so the integral is \(\ln|g(x)|\).
      • \(\int \frac{3x^{2}}{x^3+2}\,dx=\ln|x^3+2|+c\)
      • Check: differentiate the answer and you get the integrand back.
  10. Find \(\int 8xe^{x^2-3}\,dx\).

    • Spot the pair: \(g(x)=x^2-3\) and \(g'(x)=2x\).
    • The integrand is \(4g'(x)e^{g(x)}\), so the integral is \(4e^{g(x)}\).
    • \(\int 8xe^{x^2-3}\,dx=4e^{x^2-3}+c\)
    • Check: differentiate the answer and you get the integrand back.
  11. Find \(\int \frac{12}{\cos^2(3x-2)}\,dx\).

    • \(\int\frac{1}{\cos^2 u}\,du=\tan u\)
    • Divide by 3, the coefficient of x: \(12\div 3=4\)
    • \(\int\frac{12}{\cos^2(3x-2)}\,dx=4\tan(3x-2)+c\)
    • Check: differentiate and you get the integrand back.

In context

  1. A trolley slows down on a rough floor. Its velocity is \(\frac{ds}{dt}=40e^{-0.5t}\) cm/s, where \(s\) cm is the distance from the start and \(t\) is the time in seconds. When \(t=0\), \(s=0\).

    1. (a) Find \(s\) in terms of \(t\).

      • \(s=\int 40e^{-0.5t}\,dt=-80e^{-0.5t}+c\): divide by \(-0.5\), the coefficient of t.
      • When \(t=0\), \(s=0\): \(0=-80+c\), so \(c=80\).
    2. (b) Find \(s\) when \(t=4\), to 3 significant figures.

      • \(s=-80e^{-0.5\times 4}+80=69.2\) cm
  2. The number of bacteria in a dish, \(N\), grows at the rate \(\frac{dN}{dt}=\frac{600}{2t+5}\) per hour, where \(t\) is the time in hours. When \(t=0\), \(N=1000\).

    1. (a) Find \(N\) in terms of \(t\).

      • \(N=\int\frac{600}{2t+5}\,dt=300\ln(2t+5)+c\): divide by 2, the coefficient of t.
      • When \(t=0\), \(N=1000\): \(1000=300\ln 5+c\), so \(c=1000-300\ln 5\).
    2. (b) Find \(N\) when \(t=10\), to 3 significant figures.

      • \(N=300\ln(2\times 10+5)+1000-300\ln 5=1480\) bacteria

Stretch

  1. Find \(\int x\sqrt{x^2+4}\,dx\).

    • Spot the pair: \(g(x)=x^2+4\) and \(g'(x)=2x\).
    • The integrand is \(\frac{1}{2}g'(x)[g(x)]^{\frac{1}{2}}\), so the integral is \(\frac{1}{2}\times\frac{(x^2+4)^{\frac{3}{2}}}{\frac{3}{2}}\).
    • \(\int x\sqrt{x^2+4}\,dx=\frac{1}{3}(x^2+4)^{\frac{3}{2}}+c\)
    • Check: differentiate the answer and you get the integrand back.
  2. Given that \(f'(x)=\frac{8\cos x}{2+\sin x}\) and \(f(\frac{\pi}{2})=10\), find \(f(x)\), with the constant to 3 significant figures.

    • The top is a multiple of the derivative of the bottom: \(g=2+\sin x\), \(g'=\cos x\).
    • \(f(x)=8\ln(2+\sin x)+c\). The bottom is always positive, so no modulus is needed.
    • Put in the point: \(10=8\ln(3)+c\), so \(c=10-8\ln 3\).
    • \(c=1.21\), so \(f(x)=8\ln(2+\sin x)+1.21\)

jmaths.xyz · AI HL · AHL 3.2 Integrating f(ax+b) and by inspection