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IB Mathematics: Applications and Interpretation HL · AHL 1: Graph Theory · AHL 1.11
The travelling salesman: nearest neighbour Problem set A Answers
Skills
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C–D–E–A–B–C; 45 km
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A–B–C–D–E–A; 64 km
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- (a) Each town once, returns to A; length 57 km
- (b) The shortest route is at most 57 km.
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B–D–A–E–C–F–B; 80 km
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- (a) 360
- (b) 86.5 hours
In context
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A–D–F–B–E–C–A; 61 km; the shortest route is at most 61 km
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- (a) A–E–F–C–D–B–A; 55 km
- (b) E–A–D–C–F–B–E; 66 km
- (c) 55 km
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- (a) 51 km
- (b) No: a route of 51 km exists, so the shortest is at most 51.
- (c) We cannot tell. The upper bound allows it, but it may or may not be possible.
Stretch
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- (a) A–E–D–B–C–A; 62 km
- (b) A–D–C–B–E–A; 59 km (or the same cycle reversed)
- (c) No. The nearest neighbour tour is 62 km but a route of 59 km exists.
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- (a) A: 58; B: 61; C: 56; D: 58; E: 66
- (b) 56 km, tour C–E–A–D–B–C
jmaths.xyz · AI HL · AHL 1.11 The travelling salesman: nearest neighbour