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IB Mathematics: Applications and Interpretation HL · AHL 1: Graph Theory · AHL 1.11
The travelling salesman: nearest neighbour Problem set B Answers
Skills
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D–E–A–B–C–D; 37 km
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E–C–B–A–D–E; 48 km
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- (a) Each town once, returns to A; length 51 km
- (b) The shortest route is at most 51 km.
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C–A–D–E–F–B–C; 63 km
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- (a) 2520
- (b) 25.2 days
In context
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A–B–E–D–C–F–A; 75 km; the shortest route is at most 75 km
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- (a) A–F–E–B–D–C–A; 57 km
- (b) E–B–D–A–F–C–E; 67 km
- (c) 57 km
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- (a) 48 km
- (b) No: a route of 48 km exists, so the shortest is at most 48.
- (c) We cannot tell. The upper bound allows it, but it may or may not be possible.
Stretch
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- (a) A–D–E–B–C–A; 55 km
- (b) A–D–B–C–E–A; 45 km (or the same cycle reversed)
- (c) No. The nearest neighbour tour is 55 km but a route of 45 km exists.
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- (a) A: 64; B: 64; C: 72; D: 61; E: 64
- (b) 61 km, tour D–C–E–B–A–D
jmaths.xyz · AI HL · AHL 1.11 The travelling salesman: nearest neighbour