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IB Mathematics: Applications and Interpretation HL · 13.5: Integration · 13.5.9
Integration: exam review Exam review: second paper Answers
Section A: short questions
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- (a) 27 m
- (b) 139.5 m
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- (a) \(2x^{4} + 6x + \frac{5}{x^{3}} + c\)
- (b) \(x^{3} + \frac{5}{2}x^{2} - 2x + c\)
- (c) \(4x^{3} - 5x - \frac{9}{x} + c\)
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- (a) \(6x^{\frac{3}{2}} + 20\sqrt{x} + c\)
- (b) \(y=4x^{\frac{3}{2}} - 7x - 25\)
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- (a) \(-\dfrac{7}{3x^{3}}+c\)
- (b) \(x^{6}-4x^{2}+\dfrac{4}{x^{2}}\); \(\dfrac{x^{7}}{7}-\dfrac{4x^{3}}{3}-\dfrac{4}{x}+c\)
- (c) \(g(x)=12x^{3}+\dfrac{24}{x^{4}}\)
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- (a) \(y=4x^{3} + 3x + \frac{3}{x^{3}} + 4\)
- (b) 42.4
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- (a) \(f(x)=x^{4}-3x^{2}+4\)
- (b) 6.4
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- (a) \(\displaystyle\int_{2}^{6}\left(x^{2} - 8x + 18\right)dx\)
- (b) 13.3
- (c) 18.7
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- (a) \(r=9t\)
- (b) 4050 litres
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- (a) 8.963, 14.78, 24.36
- (b) 35.5
- (c) Greater than the exact value: the curve bends upwards, so the tops of the trapeziums lie above the curve.
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- (a) 4080 m²
- (b) 804 m²
- (c) 3280 m²
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- (a) 8
- (b) 16
Section B: long questions
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- (a) \(k=0.8\)
- (b) 85 litres
- (c) \(t=8.30\) minutes
- (d) The amount that flows in between \(t=3\) and \(t=7\): 22 litres
- (e) The rate keeps increasing for ever, which is not realistic: a pump cannot run faster and faster without limit.
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- (a) The distance travelled
- (b) 556 m
- (c) Less than the true distance: the curve bends downwards, so the tops of the trapeziums lie below it.
- (d) 576 m
- (e) 3.52%
- (f) 11.2 s
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- (a) \(x=12\)
- (b) \(x=8\)
- (c) \(\displaystyle\int_0^{8}\left(8x-x^{2}\right)dx\)
- (d) 85.3 m²
- (e) 288 m²
- (f) 29.6%
- (g) 68.3 m³
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- (a) \(x=2.23\) and \(x=10.8\)
- (b) \(\displaystyle\int_{2.23}^{10.8}\left((13-x)-\frac{24}{x}\right)dx\); 17.7 m²
- (c) 32.0 m²
- (d) 31.2
- (e) 2.53%
- (f) 8.86 m³
jmaths.xyz · AI HL · 13.5.9 Unit review