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IB Mathematics: Applications and Interpretation HL · AHL 5: Matrices · AHL 5.5
Systems of equations with the inverse matrix Problem set A Answers
Skills
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- (a) \(x = 3,\; y = 1\)
- (b) \(x = -2.5,\; y = 4\)
- (c) \(x = 2,\; y = -1\)
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- (a) \(x = 1,\; y = 1,\; z = 2\)
- (b) \(x = 1,\; y = 2,\; z = 3\)
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- (a) \(k = \pm 6\)
- (b) \(k = \pm 3\)
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- (a) 0
- (b) k = 8
- (c) No solutions: the lines are parallel and different.
In context
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\(\begin{pmatrix}3 & 2 \\ 4 & 5\end{pmatrix}\begin{pmatrix}c \\ t\end{pmatrix} = \begin{pmatrix}15.8 \\ 26.2\end{pmatrix}\). Coffee €3.80, tea €2.20.
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\(\begin{pmatrix}1 & 1 & 1 \\ 1 & 0 & -1 \\ 0.04 & 0.025 & 0.06\end{pmatrix}\begin{pmatrix}a \\ b \\ c\end{pmatrix} = \begin{pmatrix}40000 \\ 5000 \\ 1575\end{pmatrix}\). A $15 000, B $15 000, C $10 000.
Stretch
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\(x = \dfrac{2k - 1}{k^2 - 1},\quad y = \dfrac{k - 2}{k^2 - 1}\)
jmaths.xyz · AI HL · AHL 5.5 Systems of equations using the inverse matrix