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IB Mathematics: Applications and Interpretation HL · 13.2: Probability Distributions · 13.2.10
The Poisson distribution and its conditions Problem set B Worked solutions
Skills
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A Poisson model is suggested for the number of cars that pass a point on a quiet road each minute. Write down the three conditions that must hold, in terms of the cars.
- Independent: one car passing does not change the chance of another
- Constant average rate: the average number per minute does not change
- Singly: no two cars pass at exactly the same moment
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Cyclists pass a checkpoint independently of each other, at a constant average rate of 12 per hour. Say whether X can be modelled by a Poisson distribution. If it can, write X ~ Po(λ). If it cannot, say why not.
(a) X is the number of cyclists who pass in the next hour.
- X is the number of cyclists in a fixed hour
- The conditions hold, so X ~ Po(12)
(b) X is the number of hours, out of the next 8, in which fewer than 10 cyclists pass.
- X is the number of hours out of 8 that meet a condition
- It counts intervals, not events, so it is not Poisson (it is binomial)
(c) X is the time, in minutes, between one cyclist and the next.
- X measures the time between events
- It is not the number of events in a given period, so it is not Poisson
(d) X is the number of cyclists who pass between 8 am and 9 am tomorrow.
- X is the number of cyclists in 1 hour
- λ = 12, so X ~ Po(12)
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Each of these is to be modelled by a Poisson distribution. Say which of the three conditions is least likely to hold, and why.
(a) The number of customers who enter a restaurant each hour between 5 pm and 10 pm.
- Condition: constant average rate
- Diners arrive more around 7 pm than at 10 pm
(b) The number of pupils in a school who catch a stomach bug each week.
- Condition: independence
- If one pupil catches it, others nearby are more likely to
(c) The number of people who enter a cinema each minute in the 20 minutes before a film starts.
- Condition: singly
- Groups of friends enter together, and more arrive just before the film
In context
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A park ranger records an average of 3.1 fallen trees per week along a woodland trail. X is the number of fallen trees next week. Assume X is Poisson.
(a) Write down the distribution of X.
- X counts fallen trees in a fixed week, at an average rate of 3.1 per week
- X ~ Po(3.1)
(b) Give one reason why the conditions may not be fully met.
- A storm can bring down several trees at once, so the events are not independent
- The conditions are only roughly met, but the model is still useful
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A website receives sign-ups independently of each other, at a constant average rate of 2 per hour. X is the number of hours, out of the next 8, in which no sign-ups arrive.
(a) Explain why X is not modelled by a Poisson distribution.
- X counts the intervals that meet a condition, not the sign-ups
- There are 8 hours, so X cannot be more than 8
- X is not the number of events in a given period
(b) Y is the number of sign-ups in the next hour. Write down the distribution of Y.
- Y counts sign-ups in a fixed hour
- λ = 2, so Y ~ Po(2)
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A machine makes flaws in a long strip of metal at a constant average rate of 4 per metre, independently of each other. X is the length of strip, in metres, that must be inspected until the first flaw is found.
(a) Explain why X is not modelled by a Poisson distribution.
- X measures a length until an event
- It is not the number of events in a given length, so it is not Poisson
(b) W is the number of flaws in a 1 metre length. Write down the distribution of W.
- W counts flaws in 1 metre
- λ = 4, so W ~ Po(4)
Stretch
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For each situation, decide whether X is binomial or Poisson, and write down the distribution.
(a) A fair die is rolled 30 times. X is the number of sixes.
- Fixed number of trials: 30 rolls
- Each is a six with probability 1/6
- X ~ B(30, 1/6)
(b) Accidents happen at a junction independently, at a constant average rate of 1.5 per month. X is the number next month.
- Events at an average rate of 1.5 per month, no fixed number of trials
- X ~ Po(1.5)
(c) A tray holds 18 eggs. Each egg is cracked with probability 0.07, independently. X is the number of cracked eggs.
- Fixed number of trials: 18 eggs
- Each is cracked with probability 0.07
- X ~ B(18, 0.07)
(d) Whales are seen from a ferry independently, at a constant average rate of 4 per trip. X is the number seen on the next trip.
- Events at an average rate of 4 per trip
- X ~ Po(4)
jmaths.xyz · AI HL · 13.2.10 The Poisson distribution and its conditions