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IB Mathematics: Applications and Interpretation HL · 13.1: Probability · 13.1.7
Independent events Problem set B Answers
Skills
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P(both) = 0.165
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Not independent: P(both) = 0.15, product = 0.18
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P(B) = 0.45
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P(B) = \(\frac{2}{3}\) ≈ 0.667
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- (a) 0.58
- (b) No: independence gives P(C ∩ D) = 0.12, not 0.
In context
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- (a) \(\frac{7}{18}\) ≈ 0.389
- (b) 42 times
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- (a) \(\frac{1}{8}\) ≈ 0.125
- (b) \(\frac{11}{32}\) ≈ 0.344
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- (a) Only a car 45, both 25, only a bicycle 30, neither 60
- (b) \(\frac{3}{8}\) ≈ 0.375
- (c) \(\frac{3}{7}\) ≈ 0.429
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- (a) No: 6 is both.
- (b) Yes: P(M) × P(E) = 1/6 = P(M ∩ E).
Stretch
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0.55
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P(B) = 0.7
jmaths.xyz · AI HL · 13.1.7 Independent events