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IB Mathematics: Applications and Interpretation HL · 12.1: Sequences & Series · 12.1.10
Sequences and series: revision Problem set B One question at a time
Try each question on paper first. Open the working a line at a time, then say whether you had it.
Skills
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The sum of the first n terms of an arithmetic sequence is \(S_n=5n^2-2n\).
(a) Write down the values of \(S_1\) and \(S_2\).
- \(S_1=5(1)^2-2(1)=3\)
- \(S_2=5(2)^2-2(2)=16\)
(b) Write down the values of \(u_1\) and \(u_2\).
- \(u_1=S_1=3\)
- \(u_2=S_2-S_1=16-3=13\)
(c) Find d, the common difference.
- \(d=u_2-u_1=13-3=10\)
(d) Find \(u_{15}\).
- \(u_n=3+(n-1)(10)=10n-7\)
- \(u_{15}=3+14(10)=143\)
(e) Find the greatest value of n for which \(u_n<200\).
- \(10n-7<200\)
- From the calculator: \(n<20.7\)
- The greatest whole number is \(n=20\)
(f) Find the value of n for which \(S_n=952\).
- \(5n^2-2n=952\)
- From the calculator: \(n=14\) or \(n=−13.6\)
- n is a positive whole number: \(n=14\)
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The term \(u_4\) of an arithmetic sequence is 61 and the common difference is \(-7\). Find \(u_1\).
- \(u_4=u_1+3d\Rightarrow 61=u_1+3(-7)\)
- \(u_1=61+21=82\)
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An arithmetic sequence has \(u_{4}=5\) and \(u_{12}=61\).
(a) Find the common difference.
- \(u_1+3d=5\) and \(u_1+11d=61\)
- Subtract: \(8d=56\Rightarrow d=7\)
(b) Find the first term.
- \(u_1=5-3(7)=-16\)
(c) Find \(u_{40}\).
- \(u_{40}=-16+39(7)=257\)
(d) Find \(S_{80}\).
- \(S_{80}=\frac{80}{2}\left(2(-16)+79(7)\right)\)
- \(S_{80}=20840\)
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The term \(u_5\) of an arithmetic sequence is 26 and the common difference is \(-5\). The first and third terms of this sequence are the first two terms of a geometric sequence. Find the sixth term of the geometric sequence.
- \(u_1=26-4(-5)=46\), \(u_3=46+2(-5)=36\)
- \(r=\frac{36}{46}=\frac{18}{23}\)
- \(u_6=46\left(\frac{18}{23}\right)^5=13.5\)
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The term \(u_3\) of an arithmetic sequence is 21 and the common difference is \(-5\). The first and fourth terms of this sequence are the first two terms of an infinite geometric series. Find the sum to infinity of the geometric series.
- \(u_1=21-2(-5)=31\), \(u_4=31+3(-5)=16\)
- \(r=\frac{16}{31}\), and \(|r|<1\)
- \(S_\infty=\frac{31}{1-\frac{16}{31}}=\frac{961}{15}=64.1\)
In context
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A student saves 15 euros in the first week. Each week after that the student saves 4 euros more than the week before.
(a) Find the amount saved in week 30.
- \(u_1=15,\ d=4\)
- \(u_{30}=15+29(4)=131\)
(b) Find the total saved in the first 30 weeks.
- \(S_{30}=\frac{30}{2}\left(2(15)+29(4)\right)=2190\)
(c) The student wants to have saved at least 3000 euros. Find the least number of weeks needed.
- \(S_n=\frac n2\left(2(15)+(n-1)(4)\right)\ge3000\)
- From the calculator: \(S_n=3000\) at \(n=35.6\)
- The least whole number is \(n=36\)
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A runner runs 12 km in the first week of a training plan. Each week the runner runs 8% more than the week before. Give your answers to 3 significant figures.
(a) Find the distance run in week 10.
- Geometric: \(u_1=12,\ r=1.08\)
- \(u_{10}=12(1.08)^{9}=24\)
(b) Find the total distance run in the first 10 weeks.
- \(S_{10}=\frac{12\left(1.08^{10}-1\right)}{1.08-1}=174\)
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A forest team plants 72 trees in the first year. Each later year it plants 75% as many as the year before, and this continues for ever. Find the total number of trees planted.
- \(u_1=72,\ r=0.75\), and \(|r|<1\)
- \(S_\infty=\frac{72}{1-0.75}=288\)
Stretch
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An arithmetic sequence has \(S_{8}=104\) and \(S_{16}=400\). Find the first term and the common difference.
- \(\frac{8}{2}(2u_1+7d)=104\), so \(2u_1+7d=26\)
- \(\frac{16}{2}(2u_1+15d)=400\), so \(2u_1+15d=50\)
- Subtract: \(8d=24\), so \(d=3\)
- \(2u_1=26-7(3)\), so \(u_1=2.5\)
jmaths.xyz · AI HL · 12.1.10 Sequences and series: revision