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IB Mathematics: Applications and Interpretation HL · AHL 4: Vectors · AHL 4.11
Name Date
Constant velocity: speed, position and closest approach Problem set B
Show your working. Use the calculator for the closest approach, and give 3 significant figures unless the answer is exact.
Each question matches the question with the same number in set A. Do the ones you got wrong there.
Difficulty: first skills applying them stretch
Skills
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A cyclist moves with constant velocity \(\mathbf{v} = \begin{pmatrix} 3 \\ -8 \end{pmatrix}\) m s\(^{-1}\), where \(\begin{pmatrix} 1 \\ 0 \end{pmatrix}\) points east and \(\begin{pmatrix} 0 \\ 1 \end{pmatrix}\) points north.
- (a) Find the direction of motion as a bearing.
- (b) Find the speed.
- (c) A second object has velocity \(\begin{pmatrix} -6 \\ 5 \end{pmatrix}\) m s\(^{-1}\). Find its direction of motion as a bearing.
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A shark moves with constant speed in a fixed direction. Distances are in metres and time in seconds.
- (a) The direction is \(\begin{pmatrix} 2 \\ 3 \\ -6 \end{pmatrix}\) and the speed is 21 m s\(^{-1}\). Find the velocity vector.
- (b) The direction is \(\begin{pmatrix} -2 \\ 5 \\ 1 \end{pmatrix}\) and the speed is 9 m s\(^{-1}\). Find the velocity vector, giving each component to 3 significant figures.
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An object moves with constant velocity \(\mathbf{v} = \begin{pmatrix} 2 \\ -3 \\ -1 \end{pmatrix}\) m s\(^{-1}\). At \(t = 0\) its position vector is \(\mathbf{r}_0 = \begin{pmatrix} -5 \\ 1 \\ 8 \end{pmatrix}\) m, where \(t\) is in seconds.
- (a) Write down an equation for the position vector of the object at time \(t\).
- (b) Find the distance of the object from the origin when \(t = 3\).
In context
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Two submarines move with constant velocities. Their position vectors (in km) at time \(t\) hours are given.
- (a) \(\mathbf{r}_A = \begin{pmatrix} -2 \\ 4 \\ 3 \end{pmatrix} + t\begin{pmatrix} 3 \\ -1 \\ 2 \end{pmatrix}\) and \(\mathbf{r}_B = \begin{pmatrix} 4 \\ -5 \\ 11 \end{pmatrix} + t\begin{pmatrix} 1 \\ 2 \\ -2 \end{pmatrix}\). Show that \(A\) and \(B\) do not collide.
- (b) \(\mathbf{r}_C = \begin{pmatrix} -5 \\ 8 \\ -4 \end{pmatrix} + t\begin{pmatrix} 2 \\ -1 \\ 3 \end{pmatrix}\) and \(\mathbf{r}_D = \begin{pmatrix} 1 \\ 0 \\ 2 \end{pmatrix} + t\begin{pmatrix} -1 \\ 3 \\ 0 \end{pmatrix}\). Show that \(C\) and \(D\) collide, and find where.
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Two divers have position vectors (in m) at time \(t\) minutes: \(\mathbf{r}_A = \begin{pmatrix} 0 \\ 6 \\ 5 \end{pmatrix} + t\begin{pmatrix} 2 \\ 1 \\ -2 \end{pmatrix}\) and \(\mathbf{r}_B = \begin{pmatrix} 9 \\ -3 \\ 1 \end{pmatrix} + t\begin{pmatrix} -1 \\ 3 \\ 0 \end{pmatrix}\).
- (a) Find \(\overrightarrow{AB}\) in terms of \(t\).
- (b) Use your calculator to find the time at which they are closest together, and their distance apart at that time.
Stretch
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A search robot starts at the point with position vector \(\begin{pmatrix} -20 \\ 35 \\ -5 \end{pmatrix}\) m, relative to the control point O, and moves in the direction \(\begin{pmatrix} -2 \\ 4 \\ 1 \end{pmatrix}\) at a constant speed of 6 m s\(^{-1}\).
- (a) Find its velocity vector, giving each component to 3 significant figures.
- (b) Write down its position vector at time \(t\) seconds.
- (c) Find its distance from the control point O after 15 seconds.
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Two marine drones have position vectors (in m) at time \(t\) seconds: \(\mathbf{r}_A = \begin{pmatrix} -4 \\ 2 \\ 6 \end{pmatrix} + t\begin{pmatrix} 2 \\ -1 \\ -3 \end{pmatrix}\) and \(\mathbf{r}_B = \begin{pmatrix} 2 \\ -4 \\ -6 \end{pmatrix} + t\begin{pmatrix} -1 \\ 2 \\ 0 \end{pmatrix}\).
- (a) Show that they do not collide.
- (b) Find the time at which they are closest together, and the distance between them then.
- (c) Safety rules require at least 3 m between them at all times. Is the rule kept? Give a reason.
jmaths.xyz · AI HL · AHL 4.11 Constant velocity: speed, position and closest approach