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IB Mathematics: Applications and Interpretation HL · AHL 4: Vectors · AHL 4.8
The vector equation of a line Problem set A Answers
Skills
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- (a) \(\mathbf{r}=\begin{pmatrix}2\\5\end{pmatrix}+\lambda\begin{pmatrix}6\\-6\end{pmatrix}\)
- (b) (5, 2)
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- (a) \(\mathbf{r}=\begin{pmatrix}3\\-2\\4\end{pmatrix}+\lambda\begin{pmatrix}1\\5\\-2\end{pmatrix}\)
- (b) \(\mathbf{r}=\begin{pmatrix}4\\3\\2\end{pmatrix}+\mu\begin{pmatrix}1\\5\\-2\end{pmatrix}\)
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\(\mathbf{r}=\begin{pmatrix}1\\-2\\5\end{pmatrix}+\lambda\begin{pmatrix}2\\6\\-4\end{pmatrix}\); yes, \(\lambda=\frac{3}{2}\) fits every component
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No: \(\lambda=3\) from the first equation does not satisfy the others
In context
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- (a) \(\mathbf{r}=\begin{pmatrix}0\\0\\30\end{pmatrix}+\lambda\begin{pmatrix}80\\60\\-20\end{pmatrix}\)
- (b) Yes, \(\lambda=\frac{3}{2}\)
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- (a) \(\mathbf{r}=\begin{pmatrix}2\\-1\\3\end{pmatrix}+\lambda\begin{pmatrix}1\\2\\-2\end{pmatrix}\)
- (b) Yes, \(\lambda=5\)
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- (a) \(\mathbf{r}=\begin{pmatrix}0\\0\\40\end{pmatrix}+\lambda\begin{pmatrix}120\\50\\-40\end{pmatrix}\)
- (b) (90, 37.5, 10)
Stretch
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\(k=5\)
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- (a) \(\mathbf{r}=\begin{pmatrix}1\\-3\\2\end{pmatrix}+\lambda\begin{pmatrix}4\\6\\-8\end{pmatrix}\)
- (b) Midpoint (3, 0, −2), at \(\lambda=\frac{1}{2}\)
- (c) (13, 15, −22)
jmaths.xyz · AI HL · AHL 4.8 The vector equation of a line