jmaths
IB Mathematics: Applications and Interpretation HL · AHL 4: Vectors · AHL 4.8
The vector equation of a line Problem set B Answers
Skills
-
- (a) \(\mathbf{r}=\begin{pmatrix}-3\\4\end{pmatrix}+\lambda\begin{pmatrix}8\\-6\end{pmatrix}\)
- (b) (1, 1)
-
- (a) \(\mathbf{r}=\begin{pmatrix}-1\\6\\0\end{pmatrix}+\lambda\begin{pmatrix}4\\-3\\2\end{pmatrix}\)
- (b) \(\mathbf{r}=\begin{pmatrix}3\\3\\2\end{pmatrix}+\mu\begin{pmatrix}4\\-3\\2\end{pmatrix}\)
-
\(\mathbf{r}=\begin{pmatrix}2\\3\\-4\end{pmatrix}+\lambda\begin{pmatrix}2\\-4\\2\end{pmatrix}\); yes, \(\lambda=3\) fits every component
-
No: \(\lambda=3\) from the first equation does not satisfy the others
In context
-
- (a) \(\mathbf{r}=\begin{pmatrix}-20\\10\\45\end{pmatrix}+\lambda\begin{pmatrix}60\\-30\\-30\end{pmatrix}\)
- (b) No: \(\lambda=2\) fits two equations but not the third
-
- (a) \(\mathbf{r}=\begin{pmatrix}-3\\4\\1\end{pmatrix}+\lambda\begin{pmatrix}2\\-1\\3\end{pmatrix}\)
- (b) No: \(\lambda=4\) fits two equations but not the third
-
- (a) \(\mathbf{r}=\begin{pmatrix}0\\0\\50\end{pmatrix}+\lambda\begin{pmatrix}80\\-60\\-50\end{pmatrix}\)
- (b) (48, −36, 20)
Stretch
-
\(k=11\)
-
- (a) \(\mathbf{r}=\begin{pmatrix}-2\\4\\6\end{pmatrix}+\lambda\begin{pmatrix}4\\-6\\-8\end{pmatrix}\)
- (b) Midpoint (0, 1, 2), at \(\lambda=\frac{1}{2}\)
- (c) (10, −14, −18)
jmaths.xyz · AI HL · AHL 4.8 The vector equation of a line