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IB Mathematics: Applications and Interpretation SL · 12.5: Functions · 12.5.4
Closest point on a graph Problem set B One question at a time
Try each question on paper first. Open the working a line at a time, then say whether you had it.
Skills
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Rational functions have asymptotes.
(a) Write down the equations of the vertical and horizontal asymptotes of the graph of \(f(x)=\dfrac{4x}{x+3}\), where \(x\neq-3\).
- Denominator zero: \(x+3=0\), so the vertical asymptote is \(x=-3\)
- For large x the function tends to the ratio of the x coefficients, so the horizontal asymptote is \(y=4\)
(b) The graph of \(g(x)=\dfrac{6x}{x-q}\) has asymptotes that intersect at the point \(Q(5,\,6)\). Find the value of q.
- Vertical asymptote \(x=q\); horizontal asymptote \(y=6\)
- They meet at \((q,\,6)\)
- Compare with \((5,\,6)\): q = 5
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The graph of \(f(x)=\dfrac{3x}{x+2}\) has asymptotes that meet at \(Q(-2,\,3)\). A point \(P(x,\,y)\) on the graph is a distance \(PQ=\sqrt{(x+2)^2+\left(\dfrac{-6}{x+2}\right)^2}\) from Q.
(a) Use your calculator to find the x-coordinates of the two points on the graph closest to Q.
- Graph \(Y1=\sqrt{(x+2)^2+(-6/(x+2))^2}\)
- From the calculator: minimum at x = −4.45 and at x = 0.449
(b) Find the coordinates of these points and the shortest distance PQ.
- \(y=\dfrac{3x}{x+2}\): x = −4.45 gives y = 5.45; x = 0.449 gives y = 0.551
- The minimum value of PQ from the calculator is 3.46
In context
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A fence runs along the curve \(y=\sqrt{x}\), where x and y are in metres. A sensor is fixed at the point S(11, 0).
(a) Write an expression for the distance \(d\) between the point \((x,\,\sqrt{x})\) on the curve and the sensor S(11, 0).
- Distance between \((x,\sqrt{x})\) and \((11,0)\)
- \(d=\sqrt{(x-11)^2+(\sqrt{x})^2}=\sqrt{(x-11)^2+x}\)
(b) Find the shortest distance from the sensor S(11, 0) to the curve.
- Graph \(Y1=\sqrt{(x-11)^2+x}\)
- From the calculator: minimum at x = 10.5
- Shortest distance = 3.28 m
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The concentration of a drug in the blood is modelled by \(C(t)=\dfrac{12t}{t+3}\) mg per litre, where t is the number of hours after the dose, \(t\ge0\).
(a) Write down the equations of the vertical and horizontal asymptotes of the graph of C.
- Denominator zero: \(t+3=0\), so \(t=-3\)
- For large t, \(C\to12\), so \(C=12\)
(b) What does the horizontal asymptote tell you about the concentration?
- As t grows, C approaches 12 from below
- The model predicts a long-term concentration of 12 mg per litre
Stretch
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The point \(P(x,\,y)\) lies on the curve \(y=x^2\). The point A is \((0,\,3)\). Find the coordinates of the points on the curve that are closest to A.
- A point on the curve is \((x,\,x^2)\); the distance to \((0,\,3)\) is \(d=\sqrt{x^2+(x^2-3)^2}\)
- Graph \(Y1=\sqrt{x^2+(x^2-3)^2}\)
- From the calculator: minimums at x = −1.58 and x = 1.58
- \(y=x^2=2.50\): the points are (1.58, 2.50) and (−1.58, 2.50)
jmaths.xyz · AI SL · 12.5.4 Closest point on a graph