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IB Mathematics: Applications and Interpretation SL · 12.10: Geometry & Trigonometry · 12.10.10

Arc length and sector area Problem set B Worked solutions

Skills

  1. A cake slice is a sector of radius 9.4 cm and angle 48° at the centre. Find the length of its curved edge.

    48°9.4 cmOAB
    • \(s=\frac{48}{360}\times2\pi\times9.4=7.875\)
    • 7.87 cm
  2. A fan is a sector with radius 8.5 cm and angle 130° at the centre. Find its area.

    130°8.5 cmOAB
    • \(A=\frac{130}{360}\times\pi\times8.5^2=81.97\)
    • 82.0 cm²
  3. A curved fence of length 22 m is part of a circle and subtends an angle of 105° at the centre. Find the radius of the circle.

    105°r22 mOAB
    • \(22=\frac{105}{360}\times2\pi r\)
    • \(r=\frac{22\times360}{105\times2\pi}=12.00\)
    • r = 12.0 m
  4. A pizza slice of radius 8 cm has area 55 cm². Find the angle at the centre.

    θ8 cmOAB
    • \(55=\frac{\theta}{360}\times\pi\times8^2\)
    • \(\theta=\frac{55\times360}{\pi\times8^2}=98.48\)
    • θ = 98.5°

In context

  1. A baker cuts a segment from a circular pastry of radius 14 cm. The straight cut AB subtends an angle of 80° at the centre O. Find

    80°14 cmOAB
    1. (a) the perimeter of the segment

      • \(\text{arc}=\frac{80}{360}\times2\pi\times14=19.55\)
      • \(AB^2=14^2+14^2-2\times14\times14\cos80^\circ,\; AB=18.00\)
      • \(\text{perimeter}=19.55+18.00=37.5\) cm
    2. (b) the area of the segment

      • \(\text{sector}=\frac{80}{360}\times\pi\times14^2=136.8\)
      • \(\text{triangle}=\frac{1}{2}\times14^2\sin80^\circ=96.51\)
      • \(\text{segment}=136.8-96.51=40.3\) cm²
  2. A lighthouse beam reaches 12 km and sweeps through 110°. Find

    110°12 kmOAB
    1. (a) the area of the region

      • \(A=\frac{110}{360}\times\pi\times12^2=138.2\) km²
    2. (b) the total length of its edge (the arc and the two straight sides)

      • \(s=\frac{110}{360}\times2\pi\times12=23.04\)
      • \(\text{edge}=s+2r=23.04+24=47.0\) km
  3. A llama is tied by a 6 m rope to the outside corner of a hut that is 9 m by 8 m. The llama can graze only outside the hut. Find the area it can reach.

    270°6 mX
    • The shed fills a right angle at the corner, so the rope swings through 360° − 90° = 270°.
    • \(A=\frac{270}{360}\times\pi\times6^2=\frac{3}{4}\pi\times36=84.82\)
    • 84.8 m² (6 m is shorter than both walls, so the rope never wraps round the shed)

Stretch

  1. A circular flower bed has radius 12 m. A straight fence AB of length 16 m cuts off a segment of the bed. Find

    θ12 mOAB
    1. (a) the angle AOB at the centre

      • \(\sin\left(\frac{\theta}{2}\right)=\frac{8}{12}=0.6667\)
      • \(\frac{\theta}{2}=41.81^\circ,\; \theta=83.6^\circ\)
    2. (b) the area of the segment

      • \(\text{sector}=\frac{83.62}{360}\times\pi\times12^2=105.1\)
      • \(\text{triangle}=\frac{1}{2}\times12^2\times\sin83.62^\circ=71.55\)
      • \(\text{segment}=33.5\) m²

jmaths.xyz · AI SL · 12.10.10 Arc length and sector area