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IB Mathematics: Applications and Interpretation SL · 12.10: Geometry & Trigonometry · 12.10.9
Volumes and surface areas of solids Problem set A Worked solutions
Skills
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A cone has base radius 5.4 cm and perpendicular height 10.2 cm.
(a) Find the slant height.
- \(l=\sqrt{5.4^2+10.2^2}=11.541\) cm
- 11.5 cm
(b) Find the volume.
- \(V=\frac13\pi r^2h=\frac13\pi(5.4)^2(10.2)=311.47\)
- 311 cm³
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A cone has base radius 7 cm and slant height 18.5 cm.
(a) Find the curved surface area.
- \(\pi rl=\pi(7)(18.5)=406.84\)
- 407 cm²
(b) Find the total surface area, including the base.
- \(\pi r^2=153.94\), so total \(=406.84+153.94=560.77\)
- 561 cm²
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A sphere has radius 8.5 cm.
(a) Find its volume.
- \(\frac43\pi(8.5)^3=2572.44\)
- 2570 cm³
(b) Find its surface area.
- \(4\pi(8.5)^2=907.92\)
- 908 cm²
(c) A solid hemisphere has the same radius. Find its total surface area, including the flat face.
- Curved \(2\pi r^2=453.96\), flat face \(\pi r^2=226.98\)
- Total \(3\pi r^2=680.94\), so 681 cm²
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A sphere has volume 2500 cm³.
(a) Find the radius of the sphere.
- \(\frac43\pi r^3=2500\)
- Solve for \(r\): \(r=8.419\)
- 8.42 cm
(b) A cone has volume 330 cm³ and base radius 5 cm. Find its perpendicular height.
- \(\frac13\pi(5)^2h=330\)
- \(h=\frac{3\times330}{\pi\times25}=12.605\)
- 12.6 cm
In context
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A hemispherical bowl has internal diameter 36 cm.
(a) Find the capacity in litres.
- \(r=18\) cm, \(V=\frac23\pi(18)^3=12214.5\) cm³
- \(12214.5\div1000=12.215\) litres, so 12.2 litres
(b) How many 0.25 litre cups can be filled completely from a full bowl?
- \(12.215\div0.25=48.86\)
- 48 complete cups
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A water tower holds its water in a cylinder of radius 3.2 m and height 7.5 m, with a hemispherical top of the same radius.
(a) Find the volume.
- Cylinder \(\pi(3.2)^2(7.5)=241.27\), hemisphere \(\frac23\pi(3.2)^3=68.63\)
- Total 309.9
(b) Find the area of its curved outside surface (wall and top, not the floor).
- Wall \(2\pi(3.2)(7.5)=150.80\), curved top \(2\pi(3.2)^2=64.34\)
- Total 215.1
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A garden tower is a cuboid with a square base of side 2.8 m and height 4.5 m, with a square-based pyramid of height 1.5 m on top, with the same base.
(a) Find the total volume.
- Cuboid \(2.8\times2.8\times4.5=35.28\), pyramid \(\frac13(2.8)^2(1.5)=3.920\)
- Total 39.20
(b) Find the total area of the four sloping triangular faces.
- Slant height \(\sqrt{1.5^2+1.4^2}=2.052\)
- Four faces: \(4\times\frac12\times2.8\times2.052=11.49\)
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A solid wax sphere of radius 7.5 cm is melted and recast into 15 identical cones. Each cone has base radius 3 cm. No wax is lost. Find the perpendicular height of each cone.
- Sphere: \(\frac43\pi(7.5)^3=1767.15\) cm³
- 15 cones: \(15\times\frac13\pi(3)^2h=141.372\,h\)
- \(h=\frac{1767.15}{141.372}=12.500\), so 12.5 cm
Stretch
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A toy is a solid hemisphere of radius 5 cm fixed to the base of a cone of the same base radius. The volume of the whole toy is 450 cm³. Find the perpendicular height of the cone.
- Hemisphere: \(\frac23\pi(5)^3=261.80\)
- Cone: \(\frac13\pi(5)^2h\). Total: \(261.80+\frac13\pi(5)^2h=450\)
- \(h=\frac{3(450-261.80)}{\pi(5)^2}=7.189\), so 7.19 cm
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A conical filter has internal radius 6 cm at the top and internal depth 15 cm. It stands on its point and holds water to a depth of 10 cm.
(a) Find the radius of the liquid surface.
- \(\frac{r}{6}=\frac{10}{15}\)
- \(r=4.000\), so 4.00 cm
(b) Find the volume of liquid.
- \(\frac13\pi(4.000)^2(10)=167.55\)
- 168 cm³
(c) Find the volume of liquid as a percentage of the volume of the full container.
- Full container \(\frac13\pi(6)^2(15)=565.5\)
- \(\frac{167.55}{565.5}\times100=29.6\)%
jmaths.xyz · AI SL · 12.10.9 Volumes and surface areas of solids