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IB Mathematics: Applications and Interpretation SL · 13.5: Integration · 13.5.6
Unit mixed practice: areas, rates and accumulation Problem set B Answers
Skills
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125/6 = 20.8
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250/3 = 83.3
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- (a) P = (6, 24)
- (b) 36
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44/3 = 14.7
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\(f(x)=15x^2 - \frac{10}{x^2}\)
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- (a) x = 1.59 and x = 4.41
- (b) 1.32
In context
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\(k=0.2\); 23.3 litres
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250 litres
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- (a) 29.4 millilitres
- (b) about 30.0 millilitres
- (c) The rate is not defined at \(t=0\) and is very large just after it, so the model fails at the start. (Or: the ice would all melt in a finite time, but the model goes on for ever.)
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- (a) \(\int_0^{36}\frac{t^2}{60}\,dt\)
- (b) 259 tonnes
- (c) The total mass of grain loaded into the silo in the first 36 hours: 259 tonnes.
- (d) 26.2 hours
Stretch
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jmaths.xyz · AI SL · 13.5.6 Unit mixed practice: areas, rates and accumulation