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IB Mathematics: Applications and Interpretation SL · 12.4: Solving Equations with Technology · 12.4.6
Where two graphs meet Problem set B One question at a time
Try each question on paper first. Open the working a line at a time, then say whether you had it.
Skills
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The curve \(y = 3x^2 − 2x − 4\) and the line \(y = 2x + 5\) meet at two points. Find the coordinates of both points.
- Graph \(y = 3x^2 − 2x − 4\) and \(y = 2x + 5\).
- From the calculator: \(x = −1.19\) and \(x = 2.52\)
- Use the line for \(y\): \(y = 2.62\) and \(y = 10.0\)
- Points: \((−1.19, 2.62)\) and \((2.52, 10.0)\)
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Use your calculator to solve \(3^x = 3x^2\). Give every solution to 3 significant figures.
- Graph \(y = 3^x\) and \(y = 3x^2\).
- From the calculator: intersections at \(x = −0.451, 1.00, 3.00\)
- The graphs cross three times, so there are three solutions.
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A model is \(g(x) = 4 + 15 × 0.7^x\).
(a) Find the \(y\)-intercept of the graph of \(g\).
- Put \(x = 0\): \(g(0) = 4 + 15 × 1 = 19\)
(b) Write down the equation of the horizontal asymptote.
- \(0.7^x\) gets closer to 0 as \(x\) grows, so \(g(x)\) gets closer to 4.
- Asymptote: \(y = 4\)
(c) Solve \(g(x) = 6\).
- Graph \(y = 4 + 15 × 0.7^x\) and \(y = 6\).
- From the calculator: \(x = 5.65\)
In context
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A tennis ball is hit upwards from a balcony. Its height above the ground after \(t\) seconds is \(h = −4.9t^2 + 9t + 6.2\) metres.
(a) Find the greatest height and the time at which it is reached.
- Graph \(y = −4.9x^2 + 9x + 6.2\) for \(x \geq 0\).
- From the calculator: maximum at \(t = 0.918\), \(h = 10.3\)
(b) Find when it hits the ground.
- Set \(h = 0\): the positive root is \(t = 2.37\) s
- The other root is negative, so it is rejected.
(c) For how long is it higher than 9 m?
- Intersections with \(y = 9\): \(t = 0.397\) and \(t = 1.44\)
- Time above 9 m: \(1.44 − 0.397 = 1.04\) s
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A bakery sells \(x\) cakes a week. The weekly cost is \(C = 950 + 8x\) and the weekly revenue is \(R = 46x − 0.2x^2\), both in dollars.
(a) Find the break-even quantities.
- Graph \(y = 950 + 8x\) and \(y = 46x − 0.2x^2\).
- From the calculator: \(x = 29.6\) and \(x = 160\)
(b) Write down the smallest and the largest whole number of cakes that give a profit.
- Profit when \(R > C\): between 29.6 and 160.
- Whole numbers: 30 to 160
(c) Find the greatest weekly profit, using a whole number of cakes.
- Graph \(P = R − C = 38x − 0.2x^2 − 950\) and find the maximum.
- Maximum near \(x = 95.0\); the whole number 95 gives \(P = 855.00\)
- Greatest profit: $855.00
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The value of a laptop is \(V = 1800 × 0.78^t\) euros after \(t\) years. A student's savings are \(S = 300 + 420t\) euros, for \(0 \leq t \leq 6\).
(a) Find when the two values are equal.
- Graph \(y = 1800 × 0.78^x\) and \(y = 300 + 420x\) for \(0 \leq x \leq 6\).
- From the calculator: one intersection, at \(t = 1.94\)
(b) Which is greater after 4 years? Give both values.
- At \(t = 4\): the laptop's value = €666 and the savings = €1 980
- The savings are greater.
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A workshop makes \(n\) candles in one batch. The average cost of one candle, in euros, is \(A = 180/n + 0.5n + 4\).
(a) Use your calculator to find the value of \(n\) that gives the lowest average cost, to 3 significant figures.
- Graph \(y = 180/x + 0.5x + 4\) for \(x > 0\).
- From the calculator: minimum at \(x = 19.0\), \(y = 23.0\)
(b) The number of items must be a whole number. Find the best whole number and the average cost for it.
- Compare the whole numbers either side: \(A(18) = 23.00\), \(A(19) = 22.97\)
- The best whole number is 19, at €22.97 each.
Stretch
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The curve \(y = x^2 + 2x − 3\) and the line \(y = −x + 4\) meet at points A and B.
(a) Find the coordinates of A and B.
- Graph the curve and the line.
- From the calculator: \(x = −4.54\) and \(x = 1.54\)
- Use the line for \(y\): \(y = 8.54\) and \(y = 2.46\)
(b) Find the length of AB.
- \(AB = \sqrt{(1.54 − (−4.54))^2 + (2.46 − (8.54))^2}\)
- \(AB = 8.60\)
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A rocket is launched from the ground. Its height is \(h_1 = −4.9t^2 + 25t\) metres after \(t\) seconds. At the same moment a balloon rises steadily from a height of 5 m, so its height is \(h_2 = 5 + 3t\) metres.
(a) Find the times at which the two heights are equal.
- Graph \(y = −4.9x^2 + 25x\) and \(y = 5 + 3x\)
- From the calculator: intersections at \(t = 0.240\) and \(t = 4.25\)
(b) For how long is the rocket higher than the balloon?
- The rocket is higher between the two times.
- \(4.25 − 0.240 = 4.01\) s
jmaths.xyz · AI SL · 12.4.6 Where two graphs meet