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IB Mathematics: Applications and Interpretation SL · 13.3: Statistics · 13.3.2
Spread and standard deviation Problem set A Answers
Skills
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MAD = 3.2
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- (a) Variance = 13.2
- (b) σ = 3.63
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- (a) Mean = 31
- (b) Sum of squared deviations = 206
- (c) σ = 6.42
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- (a) Both means are 10
- (b) Route 1: σ = 1.12. Route 2: σ = 3.74
- (c) Route 2, because its standard deviation is larger
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- (a) 68%
- (b) 95%
- (c) 0.15%
In context
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- (a) Mean = 43
- (b) σ = 2.45
- (c) 4.49 standard deviations above the mean
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- (a) Mean = 17, σ = 3.29
- (b) Mean = 25, σ = 3.29
- (c) Mean = 34, σ = 6.57
- (d) Adding 8 to every value adds 8 to the mean and leaves the standard deviation the same. Multiplying every value by 2 multiplies both the mean and the standard deviation by 2.
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- (a) Mean = 4.9, σ = 0.433
- (b) Mean = 11.2, σ = 16.9
- (c) Correct: median = 4.9, IQR = 0.7. With the error: median = 4.9, IQR = 0.7
- (d) The mean and standard deviation change a lot; the median and IQR do not. With an extreme value, use the median and IQR.
Stretch
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- (a) Both means are 500; both MADs are 2.4
- (b) Machine 1: σ = 2.83. Machine 2: σ = 3.79
- (c) Machine 1, because its standard deviation is smaller
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- (a) About 136
- (b) About 5
- (c) 54 to 86
jmaths.xyz · AI SL · 13.3.2 Spread and standard deviation