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IB Mathematics: Applications and Interpretation SL · 13.3: Statistics · 13.3.2
Spread and standard deviation Problem set B Answers
Skills
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MAD = 4.4
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- (a) Variance = 14.4
- (b) σ = 3.79
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- (a) Mean = 52
- (b) Sum of squared deviations = 266
- (c) σ = 7.29
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- (a) Both means are 500
- (b) Bakery 1: σ = 1.80. Bakery 2: σ = 5.61
- (c) Bakery 2, because its standard deviation is larger
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- (a) 68%
- (b) 95%
- (c) 0.15%
In context
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- (a) Mean = 61
- (b) σ = 2.37
- (c) 2.96 standard deviations below the mean
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- (a) Mean = 25, σ = 5.02
- (b) Mean = 31, σ = 5.02
- (c) Mean = 50, σ = 10.0
- (d) Adding 6 to every value adds 6 to the mean and leaves the standard deviation the same. Multiplying every value by 2 multiplies both the mean and the standard deviation by 2.
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- (a) Mean = 36.5, σ = 3.5
- (b) Mean = 83.8, σ = 127
- (c) Correct: median = 36.5, IQR = 6. With the error: median = 36.5, IQR = 6
- (d) The mean and standard deviation change a lot; the median and IQR do not. With an extreme value, use the median and IQR.
Stretch
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- (a) Both means are 40; both MADs are 1.6
- (b) Baker 1: σ = 2. Baker 2: σ = 2.53
- (c) Baker 1, because its standard deviation is smaller
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- (a) About 272
- (b) About 10
- (c) 102 to 138
jmaths.xyz · AI SL · 13.3.2 Spread and standard deviation