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IB Mathematics: Applications and Interpretation SL · 13.3: Statistics · 13.3.2

Spread and standard deviation Problem set B Answers

Skills

  1. MAD = 4.4

    1. (a) Variance = 14.4
    2. (b) σ = 3.79
    1. (a) Mean = 52
    2. (b) Sum of squared deviations = 266
    3. (c) σ = 7.29
    1. (a) Both means are 500
    2. (b) Bakery 1: σ = 1.80. Bakery 2: σ = 5.61
    3. (c) Bakery 2, because its standard deviation is larger
    1. (a) 68%
    2. (b) 95%
    3. (c) 0.15%

In context

    1. (a) Mean = 61
    2. (b) σ = 2.37
    3. (c) 2.96 standard deviations below the mean
    1. (a) Mean = 25, σ = 5.02
    2. (b) Mean = 31, σ = 5.02
    3. (c) Mean = 50, σ = 10.0
    4. (d) Adding 6 to every value adds 6 to the mean and leaves the standard deviation the same. Multiplying every value by 2 multiplies both the mean and the standard deviation by 2.
    1. (a) Mean = 36.5, σ = 3.5
    2. (b) Mean = 83.8, σ = 127
    3. (c) Correct: median = 36.5, IQR = 6. With the error: median = 36.5, IQR = 6
    4. (d) The mean and standard deviation change a lot; the median and IQR do not. With an extreme value, use the median and IQR.

Stretch

    1. (a) Both means are 40; both MADs are 1.6
    2. (b) Baker 1: σ = 2. Baker 2: σ = 2.53
    3. (c) Baker 1, because its standard deviation is smaller
    1. (a) About 272
    2. (b) About 10
    3. (c) 102 to 138

jmaths.xyz · AI SL · 13.3.2 Spread and standard deviation