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IB Mathematics: Applications and Interpretation SL · 12.8: Voronoi Diagrams · 12.8.2
Equation of a perpendicular bisector Problem set A Answers
Skills
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- (a) Midpoint \((3, 5)\); \(y=-x+8\)
- (b) Midpoint \((5, 1)\); \(y=5x-24\)
- (c) Midpoint \((8, 4)\); \(y=\frac{1}{2}x\)
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\(y=\frac{4}{3}x+\frac{5}{3}\)
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\(2x+3y=21\)
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- (a) \(y=4\)
- (b) \(x=4\)
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\((3, 9)\)
In context
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- (a) \(y=x+1\)
- (b) M is nearer
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\(4x-5y=-5\)
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- (a) \(y=-2x+18\)
- (b) \((4, 10)\)
Stretch
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- (a) \(y=-\frac{3}{2}x+\frac{21}{2}\)
- (b) Both distances are \(5.10\)
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\((6, 3)\)
jmaths.xyz · AI SL · 12.8.2 Equation of a perpendicular bisector