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IB Mathematics: Applications and Interpretation SL · 12.8: Voronoi Diagrams · 12.8.2
Equation of a perpendicular bisector Problem set B Answers
Skills
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- (a) Midpoint \((5, 5)\); \(y=2x-5\)
- (b) Midpoint \((3, 9)\); \(y=-x+12\)
- (c) Midpoint \((7, 7)\); \(y=\frac{1}{2}x+\frac{7}{2}\)
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\(y=-\frac{4}{3}x-\frac{2}{3}\)
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\(4x-y=14\)
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- (a) \(y=1\)
- (b) \(x=-1\)
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\((-4, -5)\)
In context
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- (a) \(y=-\frac{3}{4}x+9\)
- (b) T is nearer
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\(x+2y=14\)
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- (a) \(y=5x-24\)
- (b) \((5, 1)\)
Stretch
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- (a) \(y=\frac{3}{2}x-2\)
- (b) Both distances are \(8.06\)
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\((9, 4)\)
jmaths.xyz · AI SL · 12.8.2 Equation of a perpendicular bisector