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IB Mathematics: Applications and Interpretation HL · AHL 4: Vectors · AHL 4.23
Name Date
Variable velocity in two dimensions Problem set B
Differentiate or integrate each component separately, and use the starting position to find the constants. Time is in seconds, distances in metres, and your calculator is in radians.
Each question matches the question with the same number in set A. Do the ones you got wrong there.
Difficulty: first skills applying them stretch
Skills
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Find the acceleration vector at the given time. Velocities are in m s⁻¹, time in seconds.
- (a) \(\mathbf{v} = \begin{pmatrix}4t^{2} - 7t\\5 - 3t^{3}\end{pmatrix}\), at \(t = 3\)
- (b) \(\mathbf{v} = \begin{pmatrix}5e^{4t}\\9e^{-3t}\end{pmatrix}\), at \(t = 0.4\)
- (c) \(\mathbf{v} = \begin{pmatrix}5\cos 3t\\9\sin 3t\end{pmatrix}\), at \(t = 1.5\)
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Find an expression for the position vector \(\mathbf{r}\) in metres. Velocities are in m s⁻¹, and \(\mathbf{r}_0\) is the position at \(t = 0\).
- (a) \(\mathbf{v} = \begin{pmatrix}-t^{2} + 8t\\3t^{2} + 4\end{pmatrix},\ \mathbf{r}_0 = \begin{pmatrix}-2\\5\end{pmatrix}\)
- (b) \(\mathbf{v} = \begin{pmatrix}8e^{2t}\\9e^{-3t}\end{pmatrix},\ \mathbf{r}_0 = \begin{pmatrix}1\\4\end{pmatrix}\)
- (c) \(\mathbf{v} = \begin{pmatrix}10\sin 5t\\6\cos 2t\end{pmatrix},\ \mathbf{r}_0 = \begin{pmatrix}3\\-1\end{pmatrix}\)
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Find the speed at the given time. Velocities are in m s⁻¹, time in seconds. Your calculator should be in radians.
- (a) \(\mathbf{v} = \begin{pmatrix}2t^{2} - 9t\\4t + 3\end{pmatrix}\), at \(t = 5\)
- (b) \(\mathbf{v} = \begin{pmatrix}5e^{3t}\\11e^{-2t}\end{pmatrix}\), at \(t = 0.6\)
- (c) \(\mathbf{v} = \begin{pmatrix}12\sin 2t\\5\cos 2t\end{pmatrix}\), at \(t = 1\)
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A bee flies in two dimensions in a greenhouse. Its position vector is \(\mathbf{r} = \begin{pmatrix}2t^{2} - 5t\\8\cos 3t\end{pmatrix}\) metres at time \(t\) seconds. Find its speed when \(t = 2\).
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A hot-air balloon is modelled in a vertical plane. Its velocity at time \(t\) seconds is \(\mathbf{v} = (8 + 2t)\mathbf{i} + (9 - 6t)\mathbf{j}\) m s⁻¹.
- (a) Find the angle the initial velocity makes with \(\mathbf{i}\).
- (b) Show that the acceleration is constant and find its magnitude.
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Find the distance from the origin at the given time. Displacements are in metres, time in seconds.
- (a) \(\mathbf{r} = \begin{pmatrix}t^{2} + 5t\\8 - 2t^{3}\end{pmatrix}\), at \(t = 2\)
- (b) \(\mathbf{r} = \begin{pmatrix}t^{2} - 7\\-t^{3} + 3t\end{pmatrix}\), at \(t = 3\)
In context
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A robot vacuum cleaner moves on a floor. Its position is measured in metres east and north of the charging point at the origin. Its velocity is \(\mathbf{v} = \begin{pmatrix}3t - 4\\8e^{-2t}\end{pmatrix}\) m s⁻¹, and at \(t = 0\) it is at \(\mathbf{r}_0 = \begin{pmatrix}-1\\3\end{pmatrix}\) m. Find, when \(t = 1.5\):
- (a) the acceleration
- (b) the position vector
- (c) the distance from the origin
- (d) the speed
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A model train runs on a track. Its velocity is \(\mathbf{v} = \begin{pmatrix}-15\sin 3t\\15\cos 3t\end{pmatrix}\) m s⁻¹, and at \(t = 0\) it is at \(\mathbf{r}_0 = \begin{pmatrix}5\\0\end{pmatrix}\) m. Find, when \(t = 0.9\):
- (a) the speed
- (b) the position vector
- (c) the distance from the origin. What do you notice about your answers and about the shape of the path?
Stretch
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A drone's velocity is modelled by two components. Its velocity is \(\mathbf{v} = \begin{pmatrix}t^{2} - 6t + 4\\2t - 3\end{pmatrix}\) m s⁻¹ for \(t \ge 0\). Use your calculator to find the least speed and the time at which it happens.
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A particle moves in the plane. Its velocity is \(\mathbf{v} = \begin{pmatrix}9\cos 3t\\5\sin 3t\end{pmatrix}\) m s⁻¹. Find the first time \(t > 0\) at which the particle moves parallel to \(\mathbf{j}\), and its speed then.
jmaths.xyz · AI HL · AHL 4.23 Variable velocity in two dimensions