jmaths
IB Mathematics: Applications and Interpretation SL · 12.9: Differentiation · 12.9.2
From f to f′ Problem set A Answers
Skills
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- (a) f′(x) = −2
- (b) No: f′ is the horizontal line y = −2, which never meets the x-axis
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- (a) Q
- (b) x = 1
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- (a) R
- (b) x = −1 and x = 1
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- (a) x = −1, x = 1, x = 3
- (b) \(-1<x<1\) or \(x>3\)
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- (a) x = 90 and x = 270
- (b) \(90<x<270\)
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f′(x) = 5x⁴
In context
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- (a) R
- (b) t = 2. The ball is at its highest point: it is neither rising nor falling for an instant
Stretch
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An upside-down parabola meeting the x-axis at x = −2 and x = 1, above the axis for −2 < x < 1 and below it elsewhere.
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f′ is zero at x = 0, 180 and 360. It is negative for 0 < x < 180 and positive for 180 < x < 360, with its smallest value at x = 90 and its largest at x = 270: an upside-down sine shape.
jmaths.xyz · AI SL · 12.9.2 From the graph of f to the graph of f′