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IB Mathematics: Applications and Interpretation SL · 12.9: Differentiation · 12.9.3
From f′ to f Problem set B Answers
Skills
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- (a) \(x>3\)
- (b) \(x<3\)
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- (a) \(x<-2\) or \(x>2\)
- (b) x = −2 and x = 2
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- (a) \(-3<x<-1\)
- (b) x = −1
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- (a) \(x<-3\) or \(0<x<2\)
- (b) x = −3, x = 0, x = 2
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- (a) x = 2
- (b) A minimum
- (c) A straight line with gradient −2, decreasing everywhere, with no stationary point
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- (a) 2
- (b) f is increasing for all x > 0, but its gradient gets smaller: f keeps rising and flattens out
In context
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- (a) \(0\le t<2\) or \(7<t\le 8\)
- (b) t = 7
Stretch
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Stationary point at x = 3, a minimum. f falls to x = 3 and rises after it: a U shape (like an upward parabola).
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f is increasing for all x > 0 and passes through (1, 3). It is steep near x = 1 (gradient 5) and flattens as x grows (gradient 1 at x = 5). It has no stationary point.
jmaths.xyz · AI SL · 12.9.3 From the graph of f′ back to f