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IB Mathematics: Applications and Interpretation SL · 12.9: Differentiation · 12.9.3
From f′ to f Problem set B One question at a time
Try each question on paper first. Open the working a line at a time, then say whether you had it.
Skills
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The graph shows y = f′(x), the straight line through (0, −6) and (3, 0). Write the values of x for which f is:
(a) increasing;
- f′ = 0 at x = 3
- f′ is above the axis for \(x>3\)
(b) decreasing.
- f′ is below the axis for \(x<3\)
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The graph shows y = f′(x), a parabola meeting the x-axis at x = −2 and x = 2.
(a) Write the values of x for which f is increasing.
- f is increasing where f′ is above the axis
- \(x<-2\) or \(x>2\)
(b) Write the values of x where f has a stationary point.
- Stationary points are where f′ = 0: x = −2 and 2
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The graph shows y = f′(x). It has asymptotes the dashed lines x = −3 and y = −2 and meets the x-axis at x = −1.
(a) Write the values of x for which f is increasing.
- f′ = 0 at x = −1
- For x < −3 the graph is below y = −2, so below the axis
- Above the axis only between the asymptote and x = −1
- Increasing: \(-3<x<-1\)
(b) Write the x-value of the stationary point of f.
- Stationary points need f′ = 0
- x = −1
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The graph shows y = f′(x), a cubic that meets the x-axis at x = −3, 0 and 2.
(a) Write the values of x for which f is increasing.
- f is increasing where f′ is above the axis
- \(x<-3\) or \(0<x<2\)
(b) Write the values of x where f has a stationary point.
- Stationary points where f′ = 0: x = −3, x = 0, x = 2
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The graph shows y = f′(x), the line through (0, −6) and (2, 0). A different function g has g′(x) = −2 for all x.
(a) Find the x-coordinate of the stationary point of f.
- f′ = 0 at x = 2
(b) Is it a maximum or a minimum?
- f′ is negative then positive either side of x = 2
- f falls then rises: a minimum
(c) Describe the graph of g.
- g′ is the constant −2, so the gradient of g never changes
- g is a straight line, and it is never stationary
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The graph shows y = f′(x) for x > 0. It is a decreasing curve that gets closer to the x-axis.
(a) Find the gradient of f at x = 4.
- Read the height of the f′ graph at x = 4
- f′(4) = 2
(b) Is f increasing or decreasing? Does its gradient get larger or smaller as x increases?
- f′ > 0 for all x > 0, so f is increasing
- f′ decreases towards 0, so the gradient of f gets smaller
In context
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The graph shows the rate of change of the water level in a reservoir, L′(t) centimetres per day, for 0 ≤ t ≤ 8, where L is the level in centimetres and t is the time in days. L′ meets the t-axis at t = 2 and t = 7.
(a) For which values of t is the water level falling?
- The level is falling where L′ is below the axis
- \(0\le t<2\) or \(7<t\le 8\)
(b) At what time is the water level at a local maximum?
- L′ changes from positive to negative at t = 7
- The level is highest there: t = 7
Stretch
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The graph of y = f′(x) is the line through (0, −6) and (3, 0). Describe the graph of y = f(x): where it has a stationary point, whether that is a maximum or a minimum, and its overall shape.
- f′ = 0 at x = 3
- f′ < 0 for x < 3: f falls. f′ > 0 for x > 3: f rises
- Falling then rising: a minimum at x = 3
- A U shape
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For x > 0 the graph of y = f′(x) is the decreasing curve through (1, 5), (5, 1) and (10, 0.5), getting closer to the x-axis. The graph of y = f(x) passes through (1, 3). Describe the graph of f for x > 0.
- f′ > 0 for all x > 0: f is increasing
- f′ decreases, so the gradient of f gets smaller: the curve flattens
- At (1, 3) the gradient is 5; at x = 5 it is 1
- No stationary point, since f′ is never 0
jmaths.xyz · AI SL · 12.9.3 From the graph of f′ back to f