Mathematics

Corrigé

8.15 Parallel Lines and Polygons

Pack A — Réponses

# Question Réponse
1 Two lines cross. One of the four angles is 47°. State the other three angles and name the relationship for each. 47° (vertically opposite), 133°, 133°
2 A transversal crosses two parallel lines. One alternate (Z) angle is 75°. Find the other. 75°
3 A transversal crosses two parallel lines. A corresponding (F) angle is 62°. Find the other. 62°
4 Two co-interior (allied / "C") angles between parallel lines are 110° and $x$. Find $x$. $x = 70°$
5 Find the sum of the interior angles of an $n$-sided polygon with $n = 6$. 720°
6 Find one interior angle of a regular 6-gon. 120°
7 Find the exterior angle of a regular 6-gon. 60°
8 In a triangle, two angles are 80° and 60°. Find the third. 40°
9 A pentagon has angles 100°, 110°, 95°, 105° and $x$. Find $x$. 130°
10 A regular octagon has 8 interior angles. State the size of each. 135°
11 Two parallel lines crossed by a transversal: the acute angle on the upper line is 58°. Find the corresponding angle on the lower line. 58°
12 Two parallel lines have a transversal. One angle is 70°; another (alternate) is $(x + 15)$°. Find $x$. $x = 55$
13 The exterior angle of a triangle is 110°. The two non-adjacent interior angles are equal. Find each. 55° each
14 A regular polygon has exterior angle 30°. How many sides? 12 sides
15 A regular polygon has interior angle 144°. How many sides? 10 sides
16 Two parallel lines, transversal. One angle is 75°. Find all six other angles labelled around the two intersection points. 75°, 105°, 105° at upper; 75°, 105°, 105°, 75° at lower (mirrored)
17 The interior angles of an octagon are 135°, 130°, 140°, 125°, 145°, 130°, 140°, $x$. Find $x$. $x = 135°$
18 A regular nonagon (9 sides) has interior angle? 140°
19 Two parallel lines have angles labelled $a = 65°$ on the upper and $b$ co-interior on the lower. Find $b$, then find the alternate angle to $b$ on the upper line. $b = 115°$; alternate = 115°
20 Find the angle marked $x$ in a Z-shape: two parallel lines crossed by a transversal, with $x$ alternate to $(2a + 30)°$ where $a = 25°$. $x = 80°$
21 In a parallel-lines diagram, one angle is $(4x - 12)°$ and a co-interior angle is $(2x + 30)°$. Find $x$. $x = 27$
22 A regular polygon has interior angle 150°. How many sides? Find the sum of interior angles. 12 sides; sum 1800°
23 In the diagram, two parallel lines crossed by a transversal: acute angle on the upper line is 65°. Find the obtuse co-interior on the lower; then the acute on the lower. Obtuse co-int = 115°; acute on lower = 65°
24 An irregular pentagon has angles 90°, 110°, 130°, $x$, $x + 20$. Find $x$. $x = 95°$
25 The angles around a point on a transversal between two parallel lines are $a, b, c, d$. Given $a = 70°$, find $b, c, d$. $b = 110°, c = 70°, d = 110°$
26 A regular polygon has interior angle 156°. Find the number of sides and verify with the sum formula. 15 sides; sum 2340°
27 A pentagon has interior angles in the ratio 3:4:5:6:7. Find each angle. $72°, 96°, 120°, 144°, 168°$
28 In a regular dodecagon (12 sides), find (a) interior angle, (b) exterior angle, (c) sum of interior angles. (a) 150° (b) 30° (c) 1800°
29 A regular hexagon and a regular triangle share a side. Find the angle at the join. 180° (forms a straight line: 60° triangle + 120° hexagon = 180°)
30 The bisector of the exterior angle of a regular polygon meets the polygon's side at angle 75°. Find the number of sides. 12 sides
31 Two parallel lines $\ell_1$ and $\ell_2$ are crossed by a transversal. Let $a$ be an angle on $\ell_1$ and $b$ the angle alternate to $a$ on $\ell_2$. Prove (using corresponding-angle property) that $a = b$. See working — $a = b$ via vertically opposite + corresponding
32 A regular pentagon has its interior diagonals drawn, forming a five-pointed star. Find the angle at each "point" of the star. 36°
33 The interior angles of an octagon are five angles each $x°$ and three angles each $(x + 10)°$. Find $x$. $x = 131.25°$
34 Find $x$ in a quadrilateral with angles $(x + 30)°, (2x - 10)°, (3x)°, (x + 10)°$. $x \approx 47.1°$
35 A regular $n$-gon has interior angle equal to $\dfrac{180(n-2)}{n}$. (a) Show that as $n \to \infty$ the interior approaches 180°. (b) For which $n$ is the interior > 150°? (a) Limit 180° (b) $n \geq 12$ (interior 150 for $n = 12$, > 150 for $n > 12$)
36 Two parallel lines are cut by two transversals forming a quadrilateral region. The quadrilateral has two right angles. Use angle properties to prove the remaining two angles are supplementary. Sum of all four = 360°; two right angles → remaining two = 180° (supplementary)
37 A regular polygon's interior angle is 3 times its exterior angle. Find the number of sides. 8 sides
38 Three regular polygons meet at a point with no gap and no overlap. Each interior angle of each polygon must satisfy a constraint. Find a valid combination. E.g. triangle (60°) + square (90°) + 12-gon (150°) — but 60+90+150 = 300, not 360. Try: hexagon (120°) × 3 → 360° ✓.
39 In a quadrilateral, the angles in order are $(x)°, (2x)°, (x - 10)°, (3x + 10)°$. Find $x$ and the angles. $x = 51.4°$; angles ≈ 51.4°, 102.9°, 41.4°, 164.3°
40 A pentagon has 4 interior angles each $x°$ and a 5th of $(2x + 20)°$. Find $x$. $x = 86.67°$

Pack B — Réponses

# Question Réponse
1 Two lines cross. One of the four angles is 113°. State the other three angles and name the relationship for each. 113° (vert opp), 67°, 67°
2 A transversal crosses two parallel lines. One alternate (Z) angle is 108°. Find the other. 108°
3 A transversal crosses two parallel lines. A corresponding (F) angle is 144°. Find the other. 144°
4 Two co-interior (allied / "C") angles between parallel lines are 73° and $x$. Find $x$. $x = 107°$
5 Find the sum of the interior angles of an $n$-sided polygon with $n = 8$. 1080°
6 Find one interior angle of a regular 10-gon. 144°
7 Find the exterior angle of a regular 10-gon. 36°
8 In a triangle, two angles are 80° and 60°. Find the third. 60°
9 A pentagon has angles 100°, 110°, 95°, 105° and $x$. Find $x$. 105°
10 A regular octagon has 8 interior angles. State the size of each. Same.
11 Two parallel lines crossed by a transversal: the acute angle on the upper line is 41°. Find the corresponding angle on the lower line. 41°
12 Two parallel lines have a transversal. One angle is 105°; another (alternate) is $(x + 25)$°. Find $x$. $x = 80$
13 The exterior angle of a triangle is 130°. The two non-adjacent interior angles are equal. Find each. 65° each
14 A regular polygon has exterior angle 30°. How many sides? 8 sides
15 A regular polygon has interior angle 144°. How many sides? 12 sides
16 Two parallel lines, transversal. One angle is 75°. Find all six other angles labelled around the two intersection points. Same with 60° / 120°.
17 The interior angles of an octagon are 135°, 130°, 140°, 125°, 145°, 130°, 140°, $x$. Find $x$. Same.
18 A regular nonagon (9 sides) has interior angle? ≈ 147.3°
19 Two parallel lines have angles labelled $a = 65°$ on the upper and $b$ co-interior on the lower. Find $b$, then find the alternate angle to $b$ on the upper line. Same.
20 Find the angle marked $x$ in a Z-shape: two parallel lines crossed by a transversal, with $x$ alternate to $(2a + 30)°$ where $a = 25°$. $x = 70°$
21 In a parallel-lines diagram, one angle is $(4x - 12)°$ and a co-interior angle is $(2x + 30)°$. Find $x$. $x = 36$
22 A regular polygon has interior angle 150°. How many sides? Find the sum of interior angles. 20 sides; sum 3240°
23 In the diagram, two parallel lines crossed by a transversal: acute angle on the upper line is 48°. Find the obtuse co-interior on the lower; then the acute on the lower. Obtuse 132°; acute 48°
24 An irregular pentagon has angles 90°, 110°, 130°, $x$, $x + 20$. Find $x$. $x = 117.5°$
25 The angles around a point on a transversal between two parallel lines are $a, b, c, d$. Given $a = 70°$, find $b, c, d$. Same.
26 A regular polygon has interior angle 156°. Find the number of sides and verify with the sum formula. 20 sides; sum 3240°
27 A pentagon has interior angles in the ratio 3:4:5:6:7. Find each angle. $54°, 81°, 108°, 135°, 162°$
28 In a regular dodecagon (12 sides), find (a) interior angle, (b) exterior angle, (c) sum of interior angles. Same.
29 A regular hexagon and a regular triangle share a side. Find the angle at the join. 150° (90° + 60°)
30 The bisector of the exterior angle of a regular polygon meets the polygon's side at angle 75°. Find the number of sides. Same.
31 Two parallel lines $\ell_1$ and $\ell_2$ are crossed by a transversal. Let $a$ be an angle on $\ell_1$ and $b$ the angle alternate to $a$ on $\ell_2$. Prove (using corresponding-angle property) that $a = b$. Same.
32 A regular pentagon has its interior diagonals drawn, forming a five-pointed star. Find the angle at each "point" of the star. Same.
33 The interior angles of an octagon are five angles each $x°$ and three angles each $(x + 10)°$. Find $x$. $x = 140°$
34 Find $x$ in a quadrilateral with angles $(x + 30)°, (2x - 10)°, (3x)°, (x + 10)°$. $x = 50°$
35 A regular $n$-gon has interior angle equal to $\dfrac{180(n-2)}{n}$. (a) Show that as $n \to \infty$ the interior approaches 180°. (b) For which $n$ is the interior > 150°? Same.
36 Two parallel lines are cut by two transversals forming a quadrilateral region. The quadrilateral has two right angles. Use angle properties to prove the remaining two angles are supplementary. Same.
37 A regular polygon's interior angle is 3 times its exterior angle. Find the number of sides. 12 sides
38 Three regular polygons meet at a point with no gap and no overlap. Each interior angle of each polygon must satisfy a constraint. Find a valid combination. Same.
39 In a quadrilateral, the angles in order are $(x)°, (2x)°, (x - 10)°, (3x + 10)°$. Find $x$ and the angles. Same.
40 A pentagon has 4 interior angles each $x°$ and a 5th of $(2x + 20)°$. Find $x$. $x = 78°$

Problèmes — Solutions détaillées

1

**Angles in parallel lines with algebra.** Two parallel lines are crossed by a transversal. One marked angle is $(3x + 20)°$ and the co-interior angle on the same side is $(2x + 40)°$. (a) Set up and solve an equation in $x$. (b) State the size of both angles and verify they are co-interior. (c) Find the corresponding angle of the $(3x + 20)°$ angle on the other parallel line.

Réponse

(a) $5x + 60 = 180, x = 24$ (b) 92° and 88°; sum 180° ✓ (c) 92°

(a) $(3x + 20) + (2x + 40) = 180 \Rightarrow 5x = 120 \Rightarrow x = 24$. (b) Angles: $3(24) + 20 = 92°$; $2(24) + 40 = 88°$. Sum 180° ✓. (c) Corresponding = 92°.
2

**Interior-angle polygon problem.** A regular polygon has interior angle 162°. (a) Find the exterior angle. (b) How many sides? (c) Find the sum of interior angles.

Réponse

(a) 18° (b) 20 sides (c) 3240°

(a) Ext = $180 - 162 = 18°$. (b) Sides = $360/18 = 20$. (c) Sum $= (20 - 2) \times 180 = 3240°$.
3

**Star polygon problem.** A regular pentagon has all its diagonals drawn, forming a 5-pointed star. (a) Find the interior angle of the regular pentagon. (b) Find the angle at each star tip. (c) Show that the five tip angles sum to 180°.

Réponse

(a) 108° (b) 36° (c) $5 \times 36° = 180°$

(a) Sum $= 540°$. Each $= 108°$. (b) Each tip-triangle is isosceles with two base angles $= 180 - 108 = 72°$. Tip $= 180 - 144 = 36°$. (c) $5 \times 36° = 180°$. (General result for any regular polygon star.)
4

**Two-step parallel-line problem.** In a diagram with two parallel lines $\ell_1$ and $\ell_2$, and a transversal: - The acute angle at $\ell_1$ is $(2x + 10)°$. - The vertically opposite angle is $(3x - 20)°$. (a) Use vertically-opposite-angles property to find $x$. (b) Find both angles. (c) Find the obtuse co-interior angle on $\ell_2$.

Réponse

(a) $x = 30$ (b) 70° each (c) 110°

(a) Vertically opposite angles are equal: $2x + 10 = 3x - 20 \Rightarrow x = 30$. (b) Both are $70°$. (c) Co-interior on $\ell_2$: $180 - 70 = 110°$.
5

**Mixed polygon angle problem.** A pentagon and a triangle share an edge. (a) Find the interior angles of each (regular). (b) The shared edge: what is the sum of the two interior angles at one endpoint? (c) Can a regular pentagon and a regular triangle tile a plane around a vertex?

Réponse

(a) Pentagon 108°, triangle 60° (b) 168° (c) No — 168° ≠ 360° per pair

(a) Pentagon $108°$, triangle $60°$. (b) $108 + 60 = 168°$. (c) Tiling requires angle around a point = 360°. $108 + 60 = 168$, and other combinations don't reach 360 exactly without using more shapes. So a pure pentagon + triangle tiling doesn't work.
6

**Sum-of-angles identity.** Prove that the sum of the exterior angles of any convex polygon equals 360°.

Réponse

Each interior + ext = 180°. Sum of interiors $= (n-2) \times 180$. Sum of all interior + ext = $n \times 180$. So sum of exterior = $n \times 180 - (n-2) \times 180 = 2 \times 180 = 360°$ ✓

Each vertex has one interior + one exterior = 180°. Sum over all $n$ vertices: $n \times 180°$. Subtract sum of interiors $(n-2) \times 180$: exterior sum $= n \times 180 - (n-2) \times 180 = 2 \times 180 = 360°$. ∎ This holds **for any convex polygon**, regular or not.
7

**Regular hexagon investigation.** A regular hexagon has side $a$. (a) Find the interior angle. (b) The hexagon can be split into 6 equilateral triangles. Use this to find the area in terms of $a$. (c) Find the perimeter.

Réponse

(a) 120° (b) $\tfrac{3\sqrt{3}}{2} a^2$ (c) $6a$

(a) Sum $720°$; each $120°$. (b) Each equilateral triangle has area $\tfrac{\sqrt{3}}{4} a^2$. Six of them: $\tfrac{6\sqrt{3}}{4} a^2 = \tfrac{3\sqrt{3}}{2} a^2$. (c) Perimeter $6a$.
8

**Mixed angles in a complex figure.** In a figure: two parallel lines crossed by a transversal create angles labelled $a, b, c, d$ at the upper intersection and $e, f, g, h$ at the lower. Given $a = 60°$: (a) Find $b, c, d$ at the upper intersection. (b) Find $e, f, g, h$ at the lower intersection. (c) Identify which are alternate, corresponding, co-interior, vertically opposite.

Réponse

(a) $b = 120°, c = 60°, d = 120°$ (b) $e = 60°, f = 120°, g = 60°, h = 120°$ (c) See working

Upper: vertical pairs equal: $a = c = 60$; $b = d = 120$. Lower: corresponding angles equal: $e = a = 60$, etc. So $e = 60°, f = 120°, g = 60°, h = 120°$. Relationships: alternate $a$ and $g$ (both interior, on opposite sides); corresponding $a$ and $e$; co-interior $a$ and $f$; vertically opposite $a$ and $c$, etc.
9

**Irregular polygon angles.** A pentagon has angles 100°, 110°, 95°, 130°, $x$. (a) Find $x$. (b) Classify the polygon (convex or concave). (c) If $x > 180°$, what would that mean?

Réponse

(a) $x = 105°$ (b) Convex (all < 180°) (c) Concave

(a) Sum = 540. $x = 540 - 100 - 110 - 95 - 130 = 105°$. (b) All interior angles < 180° → convex. (c) If any interior angle > 180° (reflex), the polygon is concave (has a "dent").
10

**Tiling investigation.** A regular polygon tiles the plane if its interior angle divides 360° exactly. (a) Verify that equilateral triangles, squares, and hexagons can tile. (b) Show that regular pentagons cannot tile. (c) Suggest a non-regular pentagon that could.

Réponse

(a) 60, 90, 120 all divide 360 (b) 108° does not (c) E.g. an irregular pentagon with specific angle measures

(a) Triangle 60° → $360/60 = 6$ triangles per vertex. Square 90° → 4. Hexagon 120° → 3. (b) Pentagon 108°. $360/108 = 3.33$ — not an integer. So pure regular pentagon tiling impossible. (c) Irregular pentagons with specific angle combinations can tile (e.g. the Cairo tiling using irregular convex pentagons).
11

**Parallel-line angle proof.** In a diagram, parallel lines $\ell_1$ and $\ell_2$ are crossed by transversal $t$. Show that the sum of the two co-interior angles is 180°.

Réponse

Use the fact that $a + b + c + d = 360°$ at the intersection and use alternate / vertically opposite identities.

Let the angle at $\ell_1$ on the "inside" of the parallel strip be $\alpha$, and the co-interior angle at $\ell_2$ be $\beta$. The alternate angle to $\alpha$ at $\ell_2$ (also between the parallels) is also $\alpha$ (alternate angles equal). And $\alpha$ and $\beta$ are now on a straight line at $\ell_2$, so $\alpha + \beta = 180°$. ∎
12

**Polygon side count.** A regular polygon has interior angle 144°. (a) Find the number of sides. (b) Find the sum of all interior angles. (c) Find each exterior angle. (d) Show that the interior angle of a polygon with $n + 5$ sides where this polygon has $n$ sides is bigger.

Réponse

(a) 10 (b) 1440° (c) 36° (d) Interior increases with $n$

(a) Ext = 36°. Sides = $360/36 = 10$. (b) Sum $= 8 \times 180 = 1440°$. (c) 36° each. (d) Interior angle = $180 - 360/n$. As $n$ grows, $360/n$ shrinks, so interior grows. For $n + 5 > n$: interior at $n + 5$ > interior at $n$. ✓