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IB Mathematics: Applications and Interpretation HL · AHL 5: Matrices · AHL 5.3

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Determinants Problem set A

Work in your exercise book. Questions 1, 3 and 4 by hand.

Difficulty: first skills applying them stretch

Skills

  1. Find the determinant of each matrix.

    1. (a) \(\begin{pmatrix}5 & 2 \\ 3 & 4\end{pmatrix}\)
    2. (b) \(\begin{pmatrix}-2 & 7 \\ 1 & 3\end{pmatrix}\)
    3. (c) \(\begin{pmatrix}6 & -4 \\ -3 & 2\end{pmatrix}\)
    4. (d) \(\begin{pmatrix}0 & 5 \\ -2 & 9\end{pmatrix}\)
    5. (e) \(\begin{pmatrix}0.5 & 3 \\ 2 & 8\end{pmatrix}\)
    6. (f) \(\begin{pmatrix}-4 & -1 \\ 6 & -3\end{pmatrix}\)
  2. Find the area of each triangle.

    1. (a) Vertices \((0,0),\ (6,1),\ (2,5)\)
    2. (b) Vertices \((2,1),\ (7,4),\ (3,8)\)
    3. (c) Vertices \((-1,2),\ (4,0),\ (1,6)\)
  3. Find the values of \(k\) for which each matrix has determinant zero.

    1. (a) \(\begin{pmatrix}k & 3 \\ 4 & k+1\end{pmatrix}\)
    2. (b) \(\begin{pmatrix}k-1 & 4 \\ 2 & k+1\end{pmatrix}\)
    3. (c) \(\begin{pmatrix}3 & k \\ k & 12\end{pmatrix}\)
  4. Use your calculator to find the determinant of each matrix.

    1. (a) \(\begin{pmatrix}2 & 0 & 1 \\ -1 & 3 & 4 \\ 5 & 2 & -2\end{pmatrix}\)
    2. (b) \(\begin{pmatrix}1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9\end{pmatrix}\)

Thinking about area

  1. \(A\) is the point \((3, 2)\). Give the coordinates of a point \(B\) so that the determinant of the matrix with columns \(\overrightarrow{OA}\) and \(\overrightarrow{OB}\) is:

    1. (a) zero
    2. (b) negative
    3. (c) 12
  2. Use a determinant to show that the points \((1, 2)\), \((3, 6)\) and \((6, 12)\) lie on one straight line.

  3. A quadrilateral has vertices \((0,0),\ (5,1),\ (6,5)\) and \((1,4)\), in order. Show that it is a parallelogram and find its area.

Stretch

  1. \(A = \begin{pmatrix}2 & 1 \\ 3 & 4\end{pmatrix}\) and \(B = \begin{pmatrix}1 & -2 \\ 5 & 0\end{pmatrix}\). Find \(\det A\), \(\det B\) and \(\det(AB)\). What do you notice?

  2. For \(M = \begin{pmatrix}a & b \\ c & d\end{pmatrix}\), show that \(\det(kM) = k^2 \det M\). Explain this using area.

jmaths.xyz · AI HL · AHL 5.3 Determinants