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AI SL · 13.4

Hypothesis Testing

13.4.5

One-sample t-test for a mean

13.4.5

One-sample t-test for a mean

Target: I can state H0 and H1 for a one-sample test of a mean, define μ, and choose the tail from the wording. (+4 more)

By the end of this section

Key points

When to use a t-test

  • Use a t-test to test a claim about a population mean when the population variance is not known and is estimated from the sample.
  • The assumption is that the population is normally distributed. Write it down whenever you use the test.
  • H0 gives the old or claimed value of the mean only: H0: μ = μ0. It says nothing about the variance.

Hypotheses and tails

  • Define μ in words: 'μ g is the population mean mass of a loaf.'
  • H1 has the tail the question asks for. 'Increased', 'higher' or 'greater': μ > μ0. 'Decreased' or 'less': μ < μ0. 'Changed' or 'different': μ ≠ μ0.
  • H0 and H1 use μ, the population mean. Never write the sample mean in a hypothesis.

Carrying out the test

  • With a data list, enter the data and the value μ0. With summary statistics, enter the sample mean, the sample standard deviation s and n.
  • If you are given the estimate of the population variance, take its square root to get s.
  • The calculator gives t and the p-value for the tail you choose. For a two-tailed test, compare the p-value with the full significance level, not half of it.
  • Reject H0 if p < α. A p-value above α means insufficient evidence to reject H0.

Writing the conclusion

  • Always write it in context: "There is sufficient evidence, at the 5% significance level, that the mean … has increased."
  • If p > α say "insufficient evidence". Never write "H0 is true" or "proved".
  • A two-tailed test shows that the mean has changed. It does not say which way unless you look at the sample mean.

On the calculator

One-sample t-test from a data list

  • Enter the data in a list.
  • Choose the one-sample t-test, give μ0 and the tail from H1.
  • Read t and the p-value.

Screenshot and video to come

One-sample t-test from summary statistics

  • Choose the t-test with statistics instead of a data list.
  • Enter μ0, the sample mean, the sample standard deviation s and n.
  • If you are given a variance, enter its square root.
  • Read t and the p-value.

Screenshot and video to come

Explore: t-tests for means

Each dot is one value. Drag the orange marker under a sample to move it, and the teal point at the end of its bracket to change how spread out it is. The curve below is the t distribution: the orange area is the p-value.

Sample means
Estimates of σ
Pooled estimate, sₚ
Degrees of freedom
t
p-value for H₁:

The test assumes the population is normally distributed; two samples also need equal variances. The markers move with the mouse, a finger, or the arrow keys once selected (Tab).

Drag a marker to start.

  1. Drag the orange marker until the sample mean equals the value in H₀ (or the two means are equal). What are t and the p-value? Why?
  2. Keep the means where they are and drag a teal point to make the sample less spread out. What happens to t and to the p-value? Why does the spread matter as much as the difference?
  3. Choose H₁ in the other direction from the sample. Why does the p-value become large?
  4. For the same data, compare the two-tailed p-value with the one-tailed one. How are they related?

Worked examples

Problems like the ones in class. Pick one, try it, then open the working.
An upper-tail test from a data list

A bakery says its loaves have a mean mass of 800 g. After a change of recipe the owner thinks the mean mass has increased. The masses of 8 randomly chosen loaves, in grams, are shown. Test at the 5% significance level. (a) State the hypotheses. (b) Find the t-statistic and the p-value. (c) State the conclusion in context. (d) State an assumption needed for this test.

Loaf12345678Mass (g)803811798806815801809812
Working
  1. Hypotheses

    H0: μ = 800, H1: μ > 800, where μ g is the population mean mass of a loaf.

    The owner thinks the mean has increased, so H1 has >. H0 gives the old value only.

  2. Enter the data

    From the calculator, one-sample t-test with μ0 = 800, upper tail: t = 3.30, p = 0.00655

    Put the 8 masses in a list. The calculator uses the sample's own standard deviation.

  3. Compare

    0.00655 < 0.05, so reject H0.

    Compare the p-value with the significance level, 0.05.

  4. In context

    There is sufficient evidence, at the 5% significance level, that the mean mass of a loaf has increased.

    The conclusion says what it means for the loaves.

  5. Assumption

    The masses of loaves are normally distributed.

    A t-test is only valid if the population is normal.

Video walkthrough coming
A lower-tail test from a data list

A battery maker says its batteries last a mean of 14.0 hours. A reviewer thinks the mean life is less. She tests 6 batteries and records the lives in hours. Test, at the 10% significance level, whether there is evidence that the mean life is less than 14.0 hours.

Battery123456Life (h)13.114.612.813.412.913.7
Working
  1. Hypotheses

    H0: μ = 14.0, H1: μ < 14.0

    The reviewer thinks the mean is less, so H1 has <.

  2. From the calculator

    One-sample t-test, lower tail: t = −2.14, p = 0.0426

    A negative t-statistic means the sample mean is below 14.0.

  3. Compare

    0.0426 < 0.1, so reject H0.

    Compare with the significance level, 0.10.

  4. In context

    There is sufficient evidence, at the 10% significance level, that the mean battery life is less than 14.0 hours.

    Write the conclusion about the batteries.

Video walkthrough coming
A two-tailed test at 2%

A machine is set to put 500 g of sugar in each bag. A worker thinks the mean mass has changed. The masses of 9 randomly chosen bags, in grams, are shown. Test, at the 2% significance level, whether the mean mass has changed.

Bag123456789Mass (g)498.9499.6497.4500.6496.8498.1499.7496.5498.0
Working
  1. Hypotheses

    H0: μ = 500, H1: μ ≠ 500

    'Changed' means up or down, so the test has two tails.

  2. From the calculator

    One-sample t-test, two-tailed: t = −3.43, p = 0.00892

    The calculator's p-value already includes both tails.

  3. Compare

    0.00892 < 0.02, so reject H0.

    Compare p with 0.02. Do not halve the significance level.

  4. In context

    There is sufficient evidence, at the 2% significance level, that the mean mass of a bag has changed from 500 g.

    Say the mean has changed. The sample mean is below 500 g, but a two-tailed test only shows a change.

Video walkthrough coming
A test from summary statistics

The 5 km times of the members of a running club are normally distributed with a mean of 31.5 minutes. After a training programme, a random sample of 16 members has a mean time of 29.8 minutes. The estimate of the population variance from the sample is 6.25. Test, at the 5% significance level, whether the mean time has changed.

Working
  1. Hypotheses

    H0: μ = 31.5, H1: μ ≠ 31.5

    The question asks if the mean has changed: two-tailed.

  2. Standard deviation

    s = √6.25 = 2.50

    The calculator needs the standard deviation, not the variance.

  3. Enter the statistics

    Summary statistics: x̄ = 29.8, s = 2.50, n = 16, μ0 = 31.5. From the calculator: t = −2.72, p = 0.0158

    Choose the t-test with statistics, not a data list.

  4. Compare

    0.0158 < 0.05, so reject H0.

    Compare with 0.05.

  5. In context

    There is sufficient evidence, at the 5% significance level, that the mean 5 km time has changed.

    Say what happened to the mean time.

Video walkthrough coming
Choosing the hypotheses

A tablet is advertised with a mean battery life of 10 hours. A reviewer thinks the real mean is less. She tests 12 tablets and finds a sample mean of 9.4 hours. State the null and alternative hypotheses for a one-sample t-test, defining μ.

Working
  1. Define μ

    Let μ hours be the population mean battery life of the tablets.

    Always say what μ stands for.

  2. H0

    H0: μ = 10

    H0 is the claim being tested. It uses the population mean, never the sample mean.

  3. H1

    H1: μ < 10

    The reviewer thinks the mean is less, so the test is lower-tail.

Video walkthrough coming